Answer:
C - higher volume
Explanation:
The pitch or frequency of sound that an object can produce depends upon its size and configuration . The shape of hand of all are same so the frequency of sound produced by hands of all will be almost same . Hence frequency of sound produced by the hands of Anand and Kumar would have been almost the same .
But the intensity of sound produced by them would have been different . Intensity represents energy a sound carries . Hard hitting clap will produce sound of higher intensity . Intensity of sound is also called high volume sound . So Kumar's clap will carry greater energy and hence greater volume of sound .
The elastic potential energy stored in the car's spring during the process is 3.75 J
<h3>Determination of the spring constant</h3>
From the question given above, the following data were obtained:
K = F/e
K = 15 / 0.5
K = 30 N/m
<h3>Determination of the potential energy</h3>
- Spring constant (K) = 30 N/m
PE = ½Ke²
PE = ½ × 30 × 0.5²
PE = 15 × 0.25
PE = 3.75 J
Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J
Learn more about energy stored in spring:
brainly.com/question/4280346
The kinetic energy will be greatest at the bottom of the swing motion.
The potential energy will be greatest at the highest position of the swing.
Potential energy is the energy stored in an object or system due to the position or placement of its parts. However, it is not affected by the external environment of the object or system. Kinetic energy, on the other hand, is the energy of the particles of an object or system in motion.
In an oscillating pendulum, the potential energy and gravitational kinetic energy are constantly changing. The potential and kinetic energies are maximal at extreme and intermediate positions, respectively.
Learn more about the pendulum in
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B is the correct q2ureire awej\
Vi = 0 m/s
Vf = 27 m/s
t = 9 min = 540 s
1 min = 60 s
9 min = 540 s
a = ? m/s^2.
vf = vi + at
27 = 0 + 540a
27 = 540a
27/540 = 540a/540
27/540 = a
0.05 = a.
The truck's acceleration was 0.05 m/s^2.
