Answer:
2.22m/s
Explanation:
Given parameters:
M1 = 60kg
M2 = 75kg
V1 = 0m/s
V2 = 4m/s
Unknown;
Velocity after collision = ?
Solution:
To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;
M1 V1 + M2 V2 = v(M1 + M2)
So;
60 x 0 + 75 x 4 = v (60 +75)
300 = 135v
v = 2.22m/s
Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion.
Answer:300 joules
Explanation:The formula for specific heat is:
E
=
m
c
θ
, where:
E
is the energy needed in joules,
m
is the mass in kilograms,
c
is the specific heat,
θ
is the change in temperature, Celsius of Kelvin doesn't matter.
Here,
m
=
0.125
kg
c
=
480
J/kg
∘
C
θ
=
5
∘
C
, and inputting:
E
=
0.125
⋅
480
⋅
5
E
=
300
J
of energy is needed.
