0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.
Answer: Option B
<u>Explanation:</u>
Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any
The orbit’s period is given by,
Where,
= Earth’s period
= planet’s period
= sun’s mass
= earth’s radius
Now,
As, planet mass is equal to 0.7 times the sun mass, so
Taking the ratios of both equation, we get,
Given and
I think the answer is defiantly 4 <span />
This is a conversion problem. 760 Torr is equal to 1 atmosphere. so we can can solve now. 5,550torr*(1atmosphere/760torr)=7.3atmospheres. since the two torrs cancel out with cross multiplication we are left in atmosphere units.
Answer: d₂ = 170 mGya
Explanation:
the relationship between absonbed 'd' and exposure 'E' is given as;
D(Gv) = F . x (AS/xB)
F is a conversion coefficient depending on medium
so we can simply write
d₁/d₂ = x₁/x₂
Given that;
our x₁ = 60 mAs, x₂ = 120 mAs, d₁ = 85 mGya, d₂ = ?
from the given formula,
d₂ = (x₂d₁ / x₁)
now we substitute
d₂ = (120 × 85) / 60
d₂ = 170 mGya
∴ if 120 mAa is used, the new exposure will be 170 mGya
Answer and Explanation:
Before turning a hot plate on, one should consider these points:
- Check for the leads and ensure they does not trail in liquid.
- The cable should be checked for any exposed wire before turning on in order to prevent any shock.
- Any oil residue should be wiped off of the hot plate to ensure its longevity.
- It should be placed in a stable place in order to ensure safety against any hazard.
- Thus all the above mentioned points are correct to ensure safety.