Answer: The tidal forces exerted by the moon are directly associated with the earth's rotation. Due to the strong gravitational pull of the moon, the tidal bulging appears on both the sides on earth and these are region of high tide, and there is gradual rise and fall of sea level.
Because of these tidal effect, the earth is able to rotate only once in each of the orbital period.
The slope of a speed-time graph is the acceleration represented by the graph.
All other parts of this question refer to a lab experiment or exercise
where I was not present, but Zeesam16 was. Therefore I have no data
with which to answer the rest of the question, and hope that Zeesam can
handle it.
For an uniformly accelerated motion, we can write

where

is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and

is the initial velocity.
At the maximum height, the velocity is zero, so

. Therefore we can solve to find

:
Answer:
the best graph to find the acceleration is v-t since calculating the slope averages the different experimental errors.
Explanation:
The different graphics depending on time give various information, let's examine what we can get from some
Graph of x -t. from this graph we can obtain the speed through the slope, but the acceleration is not directly obtainable
v-t chart. We can get the acceleration not through the slope and the distance traveled by the area under the curve. Obtaining acceleration is very accurate since it is an average that avoids possible errors in measurements. This is the best graph to find the acceleration
Graph of a-t In this graph the acceleration is a point on the Y axis, it gives some errors because it depends strongly on the possible experimental errors.
In conclusion, the best graph to find the acceleration is v-t since calculating the slope averages the different experimental errors.
Answer:
from O toWl Q partical is accelerating with constant magnitude. and from Q to P is decelerating with constant magnitude.
Explanation:
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