Answer:
The first one
Explanation:
waves are created by friction between wind and water surface
This is known as a molecule.
Always convert to moles when comparing compounds.
Molar mass of a compound is the sum of it's atomic molar mass units.
Mg = 24.3 g/mol Mg
O2 = 16 + 16 = 32 g/mol O2
MgO = 24.3 + 16 = 40.3 g/mol MgO
Determine the moles of each reactant/product.
2.2 g Mg * (1 mol/24.3 g Mg) = 0.09 mol Mg
3.6 O2 * (1 mol/32 g O2) = 0.1125 mol O2
2.7 g MgO * (1 mol/40.3 g MgO) = 0.067 mol MgO
Check if there's a limiting reagent. For every 1 O2 we need 2 Mg
0.1125 mol O2 * 2 = 0.225 mol Mg needed.
So Mg is a limiting reagent. We have plenty of O2 which is typically the case when oxygen is a reactant.
Figure out how much product should form based on the moles of limiting reagent. For every 2 Mg 2 MgO are formed. So it's a 1:1 ratio.
0.09 mol Mg ---> 0.09 mol MgO
compare the expected 0.09 mol MgO to the actual 0.067 mol MgO obtained. Calculate the percent obtained.
(0.067 mol MgO obtained) / (0.09 mol MgO expected) * 100 = 74.44 % yield
The formula for Keq for the first chemical reaction with
given Keq is:
<span>Keq 1 = [ HI ]^2 / [ H2 ] [ I2 ]</span>
<span>While the formula for Keq for the 2nd is:</span>
<span>Keq 2 = [ HI ] / [
H2 ]^(1/2) [ I2 ]^(1/2)</span>
We can see that the coefficients in the reaction are
equal to the exponents in the equilibrium equation. Therefore if we divide the
whole reaction by 2, then that means we have to take the square root of the
equilibrium equation. Or in this case,
Keq 2 = sqrt (Keq 1)
Keq 2 = sqrt (794)
<span>Keq 2
= 28.19</span>