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Alexandra [31]
3 years ago
12

Which of the following is true of energy? A. Energy can be created. B. Energy can be destroyed. C. Energy is constantly increasi

ng. D. Energy is conserved.
Physics
1 answer:
mariarad [96]3 years ago
3 0
Hello,

The answer is option D "<span>Energy is conserved".

Reason:

The answer to this question is option D because it seems to be the best fit. Its not option A or B because energy cannot be created nor destroyed it only can be transformed into another type of energy. It shouldn't be C because energy is not always increasing because potential energy is the amount a energy that is in a object THATS NOT MOVING....therefore your answer is option D.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonpotrit</span>
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wolverine [178]
The resistance of the lamp is apparently  50V/2A  =  25 ohms.

When the circuit is fed with more than 50V, we want to add
another resistor in series with the 25-ohm lamp so that the
current through the combination will be 2A.

In order for 200V to cause 2A of current, the total resistance
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The lamp provides 25 ohms, so we want to add another 75 ohms 
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The power delivered by the 200V mains is (200V) x (2A) = 400 watts.

The lamp dissipates ( I² · R ) = (2² · 25 ohms) = 100 watts.

The extra resistor dissipates  ( I² · R) = (2² · 75 ohms) = 300 watts.

Together, they add up to the 400 watts delivered by the mains.

CAUTION:
300 watts is an awful lot of power for a resistor to dissipate !
Those little striped jobbies can't do it. 
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300 watts is even an unusually big power resistor.
If this story actually happened, it would be cheaper, easier,
and safer to get three more of the same kind of lamp, and
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3 0
3 years ago
In an experiment, students measure the position x of a cart as a function of time t for a cart that starts at rest and moves wit
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Given :

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To Find :

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Solution :

Since, acceleration is constant.

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Putting, t = 1 s  and x = 4 m in above equation, we get :

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Therefore, the acceleration of the cart is 8 m/s².

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Calculate the acceleration of gravity as a function of depth in the earth (assume it is a sphere). You may use an average densit
Ber [7]

Solution :

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$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

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$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-2000) \times 5.5 \times 10^3\right)$

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Acceleration due to gravity at 3000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-3000) \times 5.5 \times 10^3\right)$

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Acceleration due to gravity at 4000 km depths is :

$g=G\left(\frac{4}{3}\pi (R-d) \rho\right)$

$g=6.67 \times 10^{-11}\left(\frac{4}{3}\times 3.14 \times (6371-4000) \times 5.5 \times 10^3\right)$

  $= 153.84 \times 2371 \times 10^{-8}$

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3 0
3 years ago
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DiKsa [7]
Am not sure
Have a nice day
6 0
3 years ago
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