Answer:
Increase, increase
Explanation:
For a light bulb, voltage, resistance and current follows the Ohm's law:
where
V is the voltage
R is the resistance
I is the current
In this problem, the voltage is fixed: V=120 V. We can rewrite the equation as
(1)
we see that the current is inversely proportional to the resistance: so, if we decrease the resistance of the filament, the current will increase.
Moreover, the power dissipated by the bulb is
which can be rewritten using (1) as
We see that the power dissipated is inversely proportional to the resistance: therefore, if we decrease the resistance of the filament, the power dissipated will increase.
Answer:
175 kilometers
Explanation:
50 × 3.5 = 175
or
50 x 3 = 150 +
50 x 0.5 = 25
150 + 25 = 175 kilometers
Answer:
a) 12.8 N
b) 3.2 m/s²
Explanation:
I'm guessing the period is 0.5π s.
Period of a spring in simple harmonic motion is:
T = 2π √(m/k)
Given T = 0.5π and m = 2 kg:
0.5π = 2π √(2/k)
0.25 = √(2/k)
0.0625 = 2/k
k = 32
The spring constant is 32 N/m, and the maximum displacement is 0.4 m. The maximum force can be found with Hooke's law:
F = kx
F = (32 N/m) (0.4 m)
F = 12.8 N
The acceleration can be found with Newton's second law:
∑F = ma
kx = ma
(32 N/m) (0.2 m) = (2 kg) a
a = 3.2 m/s²
What are the options for A,B,C,D? There’s arrows
It is given that the length of blade of the turbine is 58 m.
During the motion, the turbine will undergo rotational motion. Hence the radius of the circle traced by the turbine is equal to the length of the blade.
Hence radius r = 58 m.
The frequency of the turbine [f] =14 rpm.
Here rpm stands for rotation per minute.
Hence the frequency of the turbine in one second-
Here Hz[ hertz] is the unit of frequency.
The angular velocity of the turbine 
radian/second
Now we have to calculate the centripetal acceleration of the blade.
Let the linear velocity of the blade is v.
we know that linear velocity v=ωr
The centripetal acceleration is calculated as-
![=\frac{[\omega r]^2}{r}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5B%5Comega%20r%5D%5E2%7D%7Br%7D)
![=[1.465124]^2 *58](https://tex.z-dn.net/?f=%3D%5B1.465124%5D%5E2%20%2A58)
[ans]
