Answer:
Explanation:
When a charged particle is moving in a straight line, means undeflected in a crossed magnetic and electric field, it means the net force on the charged particle is zero.
magnetic force is balanced by the electric force
q v B = q E
Where, q be the charge on the particle, v be the velocity, B be the strength of magnetic field, e be the strength of electric field.
So, B = E / v
Answer:
Magnitude of electric field is 1.06 x 
V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x 
m/s
final velocity of proton = v = 0 m/s
initial point 
= 0.2 m and final point is 
= 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒
where q and m is the charge and mass of proton E is the electric field , and is the initial and final position of proton
on substituting the respected values we get,
1.023 x 
= 9.6 x 
x E
⇒ E = 1.06 x V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x V/m along negative X-direction
Answer:
5.99 m = 6 m
Explanation:
PE = m*g*h
235.2 J = (4 kg)(9.81 m/s^2)(h)
h = (235.2 J)/(9.81*4)
h = 5.99 m
h = 6 m
<span>C: electrical> light,sound and nuclear!!!!!!</span>
