The calculated mutual inductance is 8.544 x 10⁻⁵ H.
Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.
Length of the solenoid= 5.0 cm
Area of cross-section=1.0 cm²
no of spaced turns=300 turns
turns of insulated wire=180 turns
Mutual inductance (M) = μ₀μr N1N2 A/ L
=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5
=79.12 x 10⁻¹⁰ x 54000 / 5
=8.544 x 10⁻⁵ H
hence, the mutual inductance is 8.544 x 10⁻⁵ H.
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Answer: False, not all matter we encounter in everyday life exists in one of the three physical forms.
When you are Standing you produce more pressure on the ground
Power (P) in "watts" in a circuit is the product in multiplying the current (I) in "amperes" and voltage (V) in "volts".
P = I x V ; I = P / V
Substituting the given values,
I = (25 W) / (230 V) = 0.1087 amperes
Therefore, the current is approximately 0.1087 A.
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
![v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3D%289.98%29%5E%7B2%7D-2%2A9.81%2A4.88%5C%5Cv_%7Bf%7D%5E%7B2%7D%20%3D%2099.6-95.74%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B3.8544%7D%5C%5Cv_%7Bf%7D%3D1.96%5Bm%2Fs%5D)
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
