Answer:
b) volume per mol (10.237 L/mol) of the inlet gas less than of the outlet gas ( 24.378 L/mol ).
Explanation:
∴ R = 0.082 atm*L / K*mol...ideal gas constant
for entry:
T1 = 35°C + 273 = 308 K
P1 = 250 KPa * ( 0.009869 atm / KPa) = 2.467 atm
⇒(V/n)1 = (R * T1 ) / P1 = (( 0.082 atm*L / K*mol ) * (308 K )) / 2.467 atm
⇒ (V/n)1 = 10.237 L/mol ideal gas inlet
for the exit:
T2 = 35 °C + 273 = 308 K
P2 = 105 KPa * ( 0.009869 atm / KPa ) = 1.036 atm
⇒ (V/n)2 = (R * T2) / P2 = (( 0.082 * 308 )) / 1.036
⇒ (V/n)2 = 24.378 L/mol ideal gas outlet
Answer:
As per Dalton's law of Partial pressure,
The total pressure of a mixture of gases is equal to sum of partial pressure of individual components of the mixture.
So, P=P_H+P_N+P_WP=P
H
+P
N
+P
W
\implies 864\ mm=220\ mm+410\ mm+P_W\implies⟹864 mm=220 mm+410 mm+P
W
⟹ P_W=864-630=234P
W
=864−630=234 mm of Hg.
Explanation:
Hope it helps<3
Liquid antacids contain suspensions of bases like aluminum hydroxide and magnesium hydroxide. These are usually the bases that can neutralize the stomach acids.
The chemical equation representing the neutralization reaction of stomach acid, HCl and antacid, aluminum hydroxide: Three moles of hydrochloric acid reacts with one mole aluminum hydroxide to give the salt, aluminum chloride and three moles of water.
Answer:
The balloon is cooled at a constant pressure until the temperature is -11°C. What is the volume of the balloon at this stage?