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Nuetrik [128]
3 years ago
9

1. Given the following equation:

Chemistry
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

a. C₄H₁₀/O₂    =  2:13 (example)

b. O₂/CO₂      = 13:8

c. O₂/H₂O      = 13:10

d. C₄H₁₀/CO₂ =  2:8

e. C₄H₁₀/H₂O =  2:10

Explanation:

2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

The molar ratios are the same as the coefficients in front of the formulas.

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The reaction converting glycerol to glycerol-3-phosphate can be represented as: glycerol + hpo42− ⟶ glycerol-3-phosphate + h2o.
Volgvan

Answer;

Yes; this reaction be spontaneous if coupled with the hydrolysis of ATP.

Explanation;

The reaction converting glycerol to glycerol-3-phosphate (energetically unfavorable) can be coupled with the conversion of ATP to ADP (energetically favorable):

Glycerol + HPO42 ⟶glycerol-3-phosphate+H2O

ATP + H2O⟶ ADP + HPO42− + H+

6 0
4 years ago
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How many grams of NaCl (molecular weight = 58 Da) would you have to dissolve in 50ml to make a 2M stock solution? Answer:
Lerok [7]

Answer:

5.8 g

Explanation:

Molecular weight in Daltons is equivalent to the molecular weight in grams per mole.

The amount of NaCl required is calculated as follows:

(2 mol/L)(50 mL)(1 L/1000 mL) = 0.1 mol

This amount is converted to grams using the molar mass (58 g/mol).

(0.1 mol)(58 g/mol) = 5.8 g

7 0
3 years ago
Simplify - Factor a
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Answer:

Option 1

Explanation:

Option number 1 is the most compact one which indicates it is a solid

7 0
3 years ago
Clouds are formed by the ________ water
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Clouds are made of water. When water evaporates it turns into clouds. So, I think the answer is EVAPORATED water.
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3 years ago
You have a red ballooe that has a volume of 20 liters, a pressure of 1.5 atmospheres and a temperature of 28 C. What is the volu
ki77a [65]

Explanation:

The given data is as follows.

 P_{1} = 1.5 atm,     V_{1} = 20 L,  T_{1} = (28 + 273) K = 301 K

   P_{2} = 5 atm,     V_{2} = ?,  T_{2} = (50 + 273) K = 323 K

Formula to calculate the volume will be as follows.

         \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}

Putting the given values into the above formula as follows.

        \frac{P_{1} \times V_{1}}{T_{1}} = \frac{P_{2} \times V_{2}}{T_{2}}  

        \frac{1.5 atm \times 20 L}{301 K} = \frac{5 atm \times V_{2}}{323 K}  

                 V_{2} = 0.64 L

Thus, we can conclude that the change in volume of the balloon will be 0.64 L.

6 0
3 years ago
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