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3 years ago

1. Given the following equation:

Chemistry

1 answer:

CaHeK987 [17]3 years ago

3 0

Answer:

a. C₄H₁₀/O₂ = 2:13 (example)

b. O₂/CO₂ = 13:8

c. O₂/H₂O = 13:10

d. C₄H₁₀/CO₂ = 2:8

e. C₄H₁₀/H₂O = 2:10

Explanation:

2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

The molar ratios are the same as the coefficients in front of the formulas.

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Does sulfured food taste different?

Volgvan

Answer:

Yes

Explanation:

Sulfur in its pure do not have any taste and odor but many foods rich in sulfur can have a distinct odor and taste. The foods contains sulfur in very small amounts but some of the foods which are known for rich in sulfur are onion, garlic, egg, flex seeds, walnuts, meat, red bell pepper, cheese, green vegetables etc.

The foods rich in sulfur helps in fighting skin acne and fights skin infection which makes our skin brighter because of this property of sulfur it is used in skin antiseptic creme and medicines.

The intake of the excess sulfur can cause burning sensation, diarrhea, tonsils and even can cause brain damage if taken in too excess and death of the brain cells. So, the sulfur is good for health and is a remedy for our skin if taken by the natural source of food in a healthy amount.

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3 years ago

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1. which is not a component of biodiversity

Vera_Pavlovna [14]

The answer is C, i just took the k-12 test~

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3 years ago

A scientist discovered a microscopic unicellular organism with no nucleus which of the following correctly describes the organis

boyakko [2]

The correct option is this: THE ORGANISM IS A PROKARYOTES.
There are basically two types of cells, prokaryotic and eukaryotic cells. The prokaryotic cells are primitive cells which contain only a few materials which are not well organised. This type of cells is usually found in microscopic organisms. The cells lack organised nucleus and cell organelles which have membranes.<span />

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3 years ago

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8. The time period of artificial satellite in a circular orbit of radius R is T. The radius of the orbit in which time period is

Elena-2011 [213]

Explanation:

It is given that,

The time period of artificial satellite in a circular orbit of radius R is T. The relation between the time period and the radius is given by :

$T^2\propto R^3$

The radius of the orbit in which time period is 8T is R'. So, the relation is given by :

$(\dfrac{T}{T'})^2=(\dfrac{R}{R'})^3$

$(\dfrac{T}{8T})^2=(\dfrac{R}{R'})^3$

$\dfrac{1}{64}=(\dfrac{R}{R'})^3$

$R'=4\times R$

So, the radius of the orbit in which time period is 8T is 4R. Hence, this is the required solution.

4 0

3 years ago

A sucrose solution is prepared to a final concentration of 0.250 M . Convert this value into terms of g/L, molality, and mass %.

MArishka [77]

Answer:

A. 85.6 g

= 0.0856 kg.

B. 0.00027 mol/g

= 0.27 mol/kg.

C. 8.39 %

Explanation:

Given:

Molar concentration = 0.25 M

Molar weight of sucrose = 342.296 g/mol

Density of solution = 1.02 g/mL

Mass of water = 934.4 g.

Density in g/l = 1.020 g/ml * 1000ml/1 l

= 1020 g/l

Mass of solution in 1 l of solution = 1020 g

Mass of solution = mass of solvent + mass of solute

Mass of sucrose = 1020 - 934.4

= 85.6 g of sucrose in 1 l of solution.

Density of sucrose = mass/volume

= molar mass/molar concentration

= 342.296 * 0.25

= 85.6 g/l

Number of moles = mass/molar mass

= 85.6/342.296

= 0.25 mol

Molality = number of moles of solute/mass of solvent

= 0.25/934.4

= 0.00027 mol/g

% mass of sucrose = mass of sucrose/total mass of solution * 100

= 85.6/1020 * 100

= 8.39 %

6 0

3 years ago