The alloy has a density of 21.186g/cc. So for a kilogram or 1000 grams/21.186 g/cc= 45.7 cc. So the answer is 45.7 cc of the allow to make up a kilogram which shows that the density of the allow can be used to calculate the volume of a larger mass ie the kilogram.
Mole<span>: the amount of a substance that contains 6.02 x </span>10<span>. 23 respective particles of that substance. Avogadro's number: 6.02 x </span>10<span>. 23. Molar Mass: the mass of one </span>mole<span> of an element. CONVERSION FACTORS: 1 </span>mole<span> = 6.02 x </span>10<span>. 23 </span>atoms<span> 1 </span>mole<span> = </span>atomic<span> mass (g). Try: 1. How </span>many atoms<span> are in 6.5</span>moles<span> of zinc</span>
I would think that it’s C, but try to get a second opinion as well!!
