To what i see, the answer is....
C.
Answer:
Acceleration due to gravity, ![a=4.61\times 10^{-14}\ m/s^2](https://tex.z-dn.net/?f=a%3D4.61%5Ctimes%2010%5E%7B-14%7D%5C%20m%2Fs%5E2)
Explanation:
It is given that,
Mass of Pluto, ![m=1.4\times 10^{22}\ kg](https://tex.z-dn.net/?f=m%3D1.4%5Ctimes%2010%5E%7B22%7D%5C%20kg)
Distance between Neptune and Pluto, ![r=4.5\times 10^{12}\ m](https://tex.z-dn.net/?f=r%3D4.5%5Ctimes%2010%5E%7B12%7D%5C%20m)
The force of gravity is balanced by the gravitational force between Neptune and Pluto. It is given by :
![a=\dfrac{Gm}{r^2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7BGm%7D%7Br%5E2%7D)
![a=\dfrac{6.67\times 10^{-11}\times 1.4\times 10^{22}}{(4.5\times 10^{12})^2}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B6.67%5Ctimes%2010%5E%7B-11%7D%5Ctimes%201.4%5Ctimes%2010%5E%7B22%7D%7D%7B%284.5%5Ctimes%2010%5E%7B12%7D%29%5E2%7D)
![a=4.61\times 10^{-14}\ m/s^2](https://tex.z-dn.net/?f=a%3D4.61%5Ctimes%2010%5E%7B-14%7D%5C%20m%2Fs%5E2)
So, the acceleration due to gravity at Neptune due to Pluto is
. Hence, this is the required solution.
Given that,
Radius of track, r = 50 m
time , t = 9 s
velocity, v = ?
Distance covered by car in one lap around a track is equal to the circumference of the track.
C = 2 π r = 2 * 3.14 * 50
C = 314.159 m
Distance covered by car, s = 314.159 m
Velocity = distance/ time
V = 314.159 / 9
V = 34.9 m/s
The average velocity of car is 34.9 m/s.
The cloud of interstellar dust and gas that forms a star is known as a nebula. With an average surface temperature of about 737K, venus is the hottest planet. Hope this helps, and sorry your question didn't get answered in time.