Calculate the pH if the [OH-] concentration is 5.9x10-1 M.

Question 6 (3 points)

olga55 [171]

Answer:

Explanation:

Given parameters:

Molarity of KOH = 0.26M

Volume of H₂SO₄ = 19.76mL

Molarity of H₂SO₄ = 0.20M

Unknown:

Volume of KOH = ?

Solution:

This is a neutralization reaction in which an acid reacts with a base to produce salt and water:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

We solve from the known to the unknown in the reaction.

The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:

Number of moles of acid = molarity x volume

Number of moles of acid = 19.76 x 0.20 = 3.95mol

From the balanced reaction equation:

1 mole of acid reacts with 2 moles of the bases KOH

3.95mole of acid would react with 3.95moles x 2 of the base

Number of moles of reacting base = 7.90moles

To find the volume of base;

Volume of base = $\frac{number of moles of base}{molarity}$

Volume = $\frac{7.90}{0.26}$ = 30.40mL

Learn more:

Neutralization brainly.com/question/6447527

#learnwithBrainly

8 0

3 years ago

Hydrazine (N2H4) is used as rocket fuel. It reacts with oxygen to form nitrogen and water.

Marina86 [1]

Answer:

See explanation below for answers

Explanation:

This is a stochiometry reaction. LEt's write the overall reaction again:

N₂H₄ + O₂ ---------> N₂ + 2H₂O

This reaction is taking place at Standard temperature and pressure conditions (STP) which are P = 1 atm and T = 273 K. To know the volume of N₂ formed, we need to know first how many moles are formed, and this can be calculated with the reagents and the limiting reagent. Let's calculate the moles first of the reagents:

MM N₂H₄ = 32 g/mol; MM O₂ = 32 g/mol

mol N₂H₄ = 2000 / 32 = 62.5 moles

mol O₂ ? 2100 / 32 = 65.63 moles

Now that we have the moles, we need to apply the stochiometry and calculate the limiting reagent. According to the overall reaction we have a mole ratio of 1:1 between N₂H₄ and O₂, therefore:

1 mole N₂H₄ ---------> 1 mole O₂

62.5 moles ----------> X

X = 62.5 moles of O₂

But we have 65.63 moles, therefore, the limiting reactant is the N₂H₄.

We also have a 1:1 mole ratio with the N₂, so:

moles N₂H₄ = moles N₂ = 62.5 moles

Now that we have the moles, we can calculate the volume with the ideal gas equation:

PV = nRT

V = nRT / P

R: gas constant (0.082 L atm / K mol)

Replacing we have:

v = 62.5 * 0.082 * 273 / 1

V = 1399.13 L of N₂

Now, how many grams of the excess remains?, we know how many moles are reacting so, let's see how much is left:

moles remaining = 65.63 - 62.5 = 3.12 moles

then the mass of oxygen:

m = 3.12 * 32 = 100.16 g of O₂

7 0

3 years ago

Read 2 more answers

A biochemical reaction will proceed in the direction as written if:_______a. ΔG > 0.b. ΔH > 0.c. ΔG = zero.d. ΔG < 0.e.

garik1379 [7]

Answer:

ΔG < 0

Explanation:

The condition for spontaneity of a chemical reaction is that ∆G<0. Hence for any biochemical reaction to proceed as written, ∆G must have a negative value.

If ∆G >0, the reaction is not spontaneous and will not proceed as written. ∆G=0 means that the reaction has attained equilibrium.

5 0

4 years ago

Except for helium, all the elements in the last column of the periodic table have

lorasvet [3.4K]

Answer:

O

Explanation:

they have O valence electrons

4 0

3 years ago

How many lone pairs are on the central atom of BrF3?

allochka39001 [22]

Answer:

BrF3 has 2 lone pairs (4 unshared electrons)

Explanation:

8 0

3 years ago