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Nastasia [14]
3 years ago
5

Somebody please help me on this i’ll mark u the brainliest please don’t waste my answers

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

<h3>               5 < x < 27   {x - lenght of unknown side}</h3>

Step-by-step explanation:

If we have triangle of sides: a, b, c, and a < b < c (or b<a<c) then:

for triangle to exist:

                                  a + b > c

So:

if  a=11, b=16  then 11 + 16 > c     ⇒   c < 27

if a=11, c = 16 then  11 + b > 16    ⇒   b > 5

We don't know if the unknown side (x) is the longest or not, so it has to be greater than 5 and less than 27

5 < x < 27

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Someone please help. Please explain how I should do it!
Ede4ka [16]

Answer:

Step-by-step explanation:

if m and n are irrational number then the product of mn sometimes rational and sometime irrational

ex: √5 *√2=√10 irrational

ex: √8*√2=√16=4 rational

b-y=|x|+3

explain why |x|+3≥|x+3|

absolute value of any number is always positive

x           |x|+3          ≥            |x+3|

1              4              =               4             in this case equal

2             5                                5

-2             5             ≥                 1             in this case |x|+3≥|x+3|

in case of negative value of x then |x|+3>|x+3|

7 0
3 years ago
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Alchen [17]
I think it’s C not sure tho
5 0
2 years ago
I need help with this please​
harina [27]

Answer:

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Step-by-step explanation:q

7 0
3 years ago
Read 2 more answers
1. What is the area of the triangle below?<br> 10 in.<br> 7 in.
Alex787 [66]

Hi

<u>The area of a triangle is </u>

\cfrac{base*height}{2}

If we plug in the given values, we get:

\frac{10*7}{2}

Multiply in the numerator:

\frac{70}{2}

Divide:

35

Therefore, the area of the triangle is 35 inches squared.

6 0
2 years ago
Read 2 more answers
What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2
OverLord2011 [107]

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

8 0
2 years ago
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