Question

Ask Your Teacher The following data represent glucose blood levels (mg/100 ml) after a 12-hour fast for a random sample of 70 women (Reference: American Journal of Clinical Nutrition, Vol. 19, pp. 345-351). 45 66 83 71 76 64 59 59 76 82 80 81 85 77 82 90 87 72 79 69 83 71 87 69 81 76 96 83 67 94 101 94 89 94 73 99 93 85 83 80 78 80 85 83 84 74 81 70 65 89 70 80 84 77 65 46 80 70 75 45 101 71 109 73 73 80 72 81 63 74
For this problem, use six classes.

(a) Find the class width
(b) Make a frequency table showing class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies. (Give relative frequencies to 4 decimal places.
(c) Draw a histogram.

Answer 1

Answer:

See steps below

Step-by-step explanation:

First step

Order the data increasingly

45,45,46,59,59,63,64,65,65,66,67,69,69,70,70,70,71,71,71,72,72

73,73,73,74,74,75,76,76,76,77,77,78,79,80,80,80,80,80,80,81,81

81,81,82,82,83,83,83,83,83,84,84,85,85,85,87,87,89,89,90,93,94

94,94,96,99,101,101,109

Second step

Compute the range: maximum-minimum = 109-45 = 64

Third step

Divide the range by the number of classes you wish to distribute the data, in this case six, and round to the nearest greater integer.

64/6 = 10.66 (round to 11)

This number gives you the width of each class = 11

Fourth step

Construct the interval classes by making intervals of the type [a,b) starting with the first datum and adding the width of the class

[45,56), [56,67), [67,78), [78,89), [89,100), [100,111)

Make a frequency table showing class limits (the smallest and greatest data in the class), class boundaries (the endpoints of the classes), the midpoints (add the endpoints and divide by 2), frequencies (the amount of data that fall in the class), relative frequencies (frequency of the class divided by the total number of data, in this case 70) and cumulative frequencies (the sum of the frequencies of the class plus the previous ones)

See graph attached

Fifth step

Draw a histogram by making columns on the classes with a height equals to the frequency

See graph attached