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Rainbow [258]
3 years ago
5

- If I initially have a gas at a pressure of 379 mmHg, a volume of 467 mL, and a temperature of

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

301.89 mL

Explanation:

- Use combined gas law formula

- Rearrange that formula to fit values then plug them in.

- Be sure to change C to K

Hope that helped! Let me know if you need further explanation.

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iVinArrow [24]

Answer:

When these materials end up in the ocean, they support the growth and well-being of marine life.

Explanation:

This is the incorrect statement

8 0
3 years ago
Electron configurations are a shorthand form of an orbital diagram, describing which orbitals are occupied for a given element.
kipiarov [429]

Answer:

[Ar] 3d10 4s2 4p3 is shorthand, 1s22s22p63s23p63d104s24p3 long hang

Explanation:

The shorthand is made using the lowest & closest noble gas, and picking up where it leaves off as follows, and longhand is made from a followed pattern you can easily find

3 0
3 years ago
Read 2 more answers
What is an isotope ​
Andrews [41]

Answer:

each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

Explanation:

5 0
3 years ago
Read 2 more answers
A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL
snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43        

pH = 14 - pOH = 14 - 4.43 = 9.57

Now, the perchloric acid added will react with ammonia:

n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O    

n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles

Finally, we can calculate the pH of the resulting solution:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98  

pH = 14 - 4.98 = 9.02

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

5 0
3 years ago
Why will nuclear fission probably never be used directly for powering automobiles?
solmaris [256]

Answer:

IT would not

Explanation:

because the design would be too bulky and would be very unsafe.

3 0
3 years ago
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