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3 years ago

A newborn eats 8 times a day. At each feeding, he eats 2.5 ounces of formula. How many days would it take to eat 100 ounces

Chemistry

2 answers:

IrinaVladis [17]3 years ago

7 0

Answer:

It will take 5 days to eat 100 ounces.

Explanation:

He eats 8 times a day.

Each time he eats, he eats 2.5 ounces.

This means that he eats 20 ounces a day, since 8 x 2.5 is 20.

We now know that he eats 20 ounces a day.

To figure out many days it would take for him to eat 100 ounces, we set up an equation.

20x = 100

The x represents the number of days that it will take for him to eat 100 ounce, and the 20 represents the number of ounces that he eat a day.

20x = 100

Divide both sides by 20, to make solve for x.

20x = 100

/20 /20

x = 5

It will take 5 days for the baby to eat 100 ounces.

fredd [130]3 years ago

6 0

Answer:

It would take 5 days

Explanation:

1. 2.5 times 8 is 20 ounces

2. 2.5 times 16 is 40 ounces

3. 2.5 times 24 is 60 ounces

4. 2.5 times 32 is 80 ounces

5. 2.5 times 40 is 100 ounces

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How many electrons in an atom could have these sets of quantum numbers?

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If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem

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Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CuCl₂: 1 mole
NaNO₃: 2 moles
Cu(NO₃)₂ : 1 mole
NaCl: 2 moles

The molar mass of the compounds is:

CuCl₂: 134.44 g/mole
NaNO₃: 85 g/mole
Cu(NO₃)₂ : 187.54 g/mole
NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
NaNO₃: 2 moles ×85 g/mole= 170 grams
Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
NaCl: 2 moles ×58.45 g/mole= 116.9 grams

<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

$mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}$

<u><em>mass of NaCl= 1.739 grams</em></u>

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

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