Answer: The energy of activation for the chirping process is 283.911 kJ/mol
Explanation:
According to the Arrhenius equation,
The expression used with catalyst and without catalyst is,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate of reaction at 
= 194/min
= rate of reaction at 
= 47.6 /min
= activation energy
R = gas constant = 8.314 J/Kmol
tex]T_1[/tex] = initial temperature = 
tex]T_1[/tex] = final temperature = 
Now put all the given values in this formula, we get
![\frac{194}{47.6}=\frac{E_a}{2.303\times 8.314}[\frac{1}{278}-\frac{1}{301}]](https://tex.z-dn.net/?f=%5Cfrac%7B194%7D%7B47.6%7D%3D%5Cfrac%7BE_a%7D%7B2.303%5Ctimes%208.314%7D%5B%5Cfrac%7B1%7D%7B278%7D-%5Cfrac%7B1%7D%7B301%7D%5D)
Thus the energy of activation for the chirping process is 283.911 kJ/mol
<span>(2.25moles)*(6.022x10^23) </span>
The statement that best describes the trend in first ionization enery of elements on the periodic table is:
<span>It generally decreases down a group because valence electrons are farther from the nucleus.
The first ionization energy measures how difficult is to release an electron from the outermost shell. The higher the ionization energy the more difficult it is to release an electron, the lower the ionication energy the easier to release an electron.
As the atomic number of the atom increases (which is what happens when you go down a group) the furthest the outermost shell of electrons will be (the size of the atoms increases) and so those electrons require less energy to be released, which means that the ionization energy decreases.
</span>
Answer:
Ch4 + 2O2 ----> CO2 + 2H2O
Explanation:
Ch4 has 4H, 1C
O2 has 2 O2
CO2 has 1 C, 2O
H2O has 1 H, 2O
you need to add 2 to O2 to balance it. Add 2 to H2O to balance the H and O
Answer:
It seems maybe A is correct answer
