By definition, centripetal acceleration is given by:
Where,
v: tangential disk speed
r: disk radius
Substituting values in the given equation we have:
Rounding the result we have:
Answer:
The centripetal acceleration of the disc edge in m/s^2 is:
Answer:
Explanation:
It is required that the weight of Joe must prevent Simon from being pulled down . That means he is not slipping down but tends to be towed down . So in equilibrium , force of friction will act in upward direction on Simon.
Let in equilibrium , tension in rope be T
For balancing Joe
T = M g
For balancing Simon
friction + T = mgsinθ
μmgcosθ+T = mgsinθ
μmgcosθ+Mg = mgsinθ
M = (msinθ - μmcosθ)
M = m(sinθ - μcosθ)
Answer:
97 s
Explanation:
Given:
Δx = 9600 m
v₀ = 198 m/s
v = 0 m/s
Find: t
Δx = ½ (v + v₀) t
9600 m = ½ (0 m/s + 198 m/s) t
t = 97 s
Answer:
d ............................
