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3 years ago

Which characeristic makes omasis different from diffusion.

1 answer:

5 0

<span>haha I used to think biology was so hard, i find it quite easy now.
Okay, so basically Osmosis is the movement of water molecules from a higher concentration to a lower concentration. Diffusion is generally the movement of a gradient from higher concentration to an area of lower concentration. Osmosis applies to water only, whereas diffusion, you have many types such as Passive transport [ movement of molecules from high- low, NO CELLULAR ENERGY needed! ] then you have faciliated diffusion ( basically uses a channel protein to allow big substances to go through the membrane : NO ENERGY needed]
OSMOSIS, the important thing to remember is that water ALWAYS flow towards the region with the higher concentration of the solute (ex: Salt is solute, water is solvent) solute is the thing that is being dissolved. Solvent is the one doing the dissolving. Hope this helped!</span>

You might be interested in

As pressure increases, temperature must ______________ for water to remain in a gaseous state.

Katyanochek1 [597]

As the pressure goes up, the temperature also goes up, and vice-versa.
<span>Also same as before, initial and final volumes and temperatures under constant pressure can be calculated.</span>

6 0

3 years ago

A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th

Ber [7]

Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

Electron mobility, u = 3900

Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

5461.4964 / 10000

0.546 ohm / μm

7 0

2 years ago

A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend

nikitadnepr [17]

The radius of curvature of the proton's path while in the field is $66.67$ × $10^{-2}$ .

b) Let R = radius curvature of protons path. Then,

relation b/w B, R, and v is: -

$B = mv/eR\\R=mv/eB$

$R=\frac{1.6*10^{-27} * 20*10^{6}}{1.6*10^{-19}*0.3 }$

$R =66.67$ × $10^{-2}$

Hence, the radius of curvature of the proton's path while in the field is $66.67$ × $10^{-2}$ .

<h3>What do you mean by Magnetic field?</h3>

The magnetic influence on moving electric charges, electric currents and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field. The magnetic field of a permanent magnet pulls on ferromagnetic substances like iron and attracts or repels other magnets. A magnetic field that varies with location will also exert a force on a variety of non-magnetic materials by changing the velocity of those particles' outer electrons. Electric currents, like those utilized in electromagnets, and electric fields that change in time produce magnetic fields that surround magnetized things.

To know more about Magnetic Field visit:

brainly.com/question/14848188

#SPJ4

5 0

1 year ago

A stone is thrown from a cliff and lands in the sea. Air resistance is negligible. Which statement is correct whilst the stone i

erik [133]

Since the stone is travelling, the displacement cannot be constant. This leaves the last 2 choices as possibilities. Now consider the acceleration that can act on the stone. Acceleration due to gravity is the only one. That means the horizontal component of the stone has to be constant since there is no acceleration in the horizontal direction.

4 0

3 years ago

What are possible units for impulse? Check all that apply.

Neporo4naja [7]

Units of impulse: N • s, kg • meters per second

Explanation:

Impulse is defined in two ways:

Impulse is defined as the product between the force exerted in a collision and the duration of the collision:

$I=F\Delta t$