Question

1. A satellite (mass = 4.44 x 109 kg) travels in orbit around the Earth at a distance of 1.9 x 10'm above

Answer 1

Answer:

The force of gravitational attraction between the satellite and Earth is $2.587\times 10^{10}$ newtons.

Explanation:

Statement is incorrect. Correct statement is:

A satellite ($m = 4.44\times 10^{9}\,kg$) travels in orbit around the Earth at a distance of $1.9\times 10^{6}\,m$ above Earth's surface. What is the force of gravitational attraction between the satellite and Earth?

The gravitational force experimented by the satellite ($F$), in newtons, is calculated by Newton's Law of Gravitation, whose equation is defined by following formula:

$F = \frac{G\cdot m \cdot M}{R^{2}}$ (1)

Where:

$G$ - Gravitational constant, in cubic meters per kilogram-square second.

$m$ - Mass of the satellite, in kilograms.

$M$ - Mass of the Earth, in kilograms.

$R$ - Distance of the satellite with respect to the center of the Earth, measured in meters.

If we know that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$, $m = 4.44\times 10^{9}\,kg$, $M = 5.972\times 10^{24}\,kg$ and $R = 8.271\times 10^{6}\,m$, then the force of gravitational attraction between the satellite and Earth is:

$F = 2.587\times 10^{10}\,N$

The force of gravitational attraction between the satellite and Earth is $2.587\times 10^{10}$ newtons.