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3 years ago

12

an object moving North with an initial velocity of 14 m s accelerates 5 Ms ^2 for 20 seconds what is the final velocity of the o

bject

2 answers:

kogti [31]3 years ago

8 0

Answer:

The final velocity of the object is 114 m/s.

Explanation:

It is given that,

Initial velocity of the object, u = 14 m/s

Acceleration of object, $a=5\ m/s^2$

Time taken, t = 20 s

Let v is the final velocity of the object. It can be calculated using first equation of motion as :

$v=u+at$

$v=14\ m/s+5\ m/s^2\times 20\ s$

v = 114 m/s

So, the final velocity of the object is 114 m/s. Hence, this is the required solution.

bonufazy [111]3 years ago

7 0

The final velocity is 114m/s
$5 = \frac{x - 14}{20} \\ x = \frac{20 \times 5}{1} + 14 = 100 + 14 \\ 114$

good luck

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A small rock is thrown straight up with initial speed v0 from the edge of the roof of a building with height H. The rock travels

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Therefore, the total displacement throughout the rock's journey is

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$y_{tot} =\dfrac{2gH+v_0^2}{2g}+\dfrac{2gH+v_0^2}{2g}+H$

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Now wee need to figure out the time of the journey.

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we solve for $t_0$ using the quadratic formula and take the positive value to get:

$t_0=\dfrac{-v_0+\sqrt{v_0^2+2gH} }{g}$

Therefore the total time is

$t_{tot}= 2\dfrac{v_0}{g}+\dfrac{-v_0+\sqrt{v_0^2+2gH} }{g}$

$\boxed{t_{tot}= \dfrac{v_0+\sqrt{v_0^2+2gH} }{g}}$

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$v_{avg}=\dfrac{y_{tot}}{t}$

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Answer:

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When electromagnetic radiation reaches a material, its propagation is by a process that we call absorption and reflection,

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