Answer: A
si, di, are expressed as negative and f is expressed as positive values.
Explanation:
When the object is located at a location in front of the focal point of a convex len, the image will always be located somewhere on the same side of the lens as the object. The image is located behind the object. In this case, the image will be an upright image and the image is enlarged
In this question, the relationship between the focal length, image distance di and object distance is
I/f = 1/di + 1/do that is
I/f - 1/di - 1/do = 0
The image size si is also negative since the image is a virtual image.
Therefore, si, di, are expressed as negative, f is expressed as positive values.
Answer:
ΔV = -0.97 m³/ kg
ΔH = 0 kJ/ kg
Explanation:
<u>To determine the change in the </u><u>specific volume</u><u> we need to </u><u>use the ideal gas law</u><u>:</u>
<em>where</em><em> P</em><em>: </em><em>pressure </em><em>of the gas </em><em>V</em><em>: </em><em>volume </em><em>of the gas, </em><em>R</em><em>: i</em><em>deal gas constant</em><em>= 0.4119 kJ/kg.K = 0.4119 kPa.m³/kg.K and </em><em>T</em><em>: </em><em>temperature </em><em>of the gas.</em>
<u />
<u>The </u><u>V₁,</u><u> at a compressed pressure is:</u>


<u>Similarly, the </u><u>V₂</u><u> is:</u>


Now, the change in the specific volume because the compressor is:

Finally, to calculate the change in the specific enthalpy, we need to remember that neon is an ideal gas and that is an isothermal process:
Have a nice day!
Answer:
That's essentially how objects in orbits work as they move closer to the body they orbit, they accelerate faster and faster. Our penny will get so fast that, once it comes around the planet, it will be flung very far away, which will then slow it down. This is what creates an elliptical orbit.
Explanation:
Answer:
The rocket above the ground is in 44 sec.
Explanation:
Given that,
Initial velocity = 92 m/s
Acceleration = 4 m/s²
Altitude = 1200 m
Suppose, How long was the rocket above the ground?
We need to calculate the time
Using equation of motion

Put the value into the formula



We need to calculate the velocity
Using equation of motion

Put the value into the formula


When the rocket hits the ground,
Then, h'=0
We need to calculate the time
Using equation of motion

Put the value into the formula



When the rocket is in the air it is the sum of the time when it reaches 1000 m and the time when it hits the ground
So, the total time will be


Hence, The rocket above the ground is in 44 sec.
The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t =

, at = v, so