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Nostrana [21]
3 years ago
7

A hiker determines the length of a lake by listening for the echo of her shout reflected by a cliff at the far end of the lake.

She hears the echo 2.91 s after shouting. Determine the length of the lake. Speed of sound in air is 343 m/s.
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
8 0

Answer:

L = 499 m

Explanation:

  • If we assume that the speed of sound is constant, that travels along a straight line, and that the echo is instantaneous, we can find the total distance travelled by the sound, as follows, just applying the definition of average velocity:

       \Delta x = v_{s} * t = 343 m/s* 2.91 s = 998 m

  • If we assume that the time needed to reach to the cliff, is the same used for the return travel, the length of the lake will be exactly half of the total distance calculated:

        l_{lake} = \frac{\Delta x}{2} = \frac{998m}{2} = 499 m

  • The length of the lake is 499 m.
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Joey drives along the 110 South freeway and notices a mile marker that reads 260 miles. He drives until he reaches the 150 mile
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Answer:

85 miles .

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Displacement along the 110 South freeway = 260 - 150  =  110 miles

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8 0
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(b) The particle displacement y of air molecules due to a sound wave is given by y 4m and w = = 0.008 cos wt sin kz. Where k - m
serious [3.7K]

The distance between two consecutive nodes and the amplitude after 0.56s are m/2 and 1.75×10^(-4) m respectively.

<h3>What's the distance between consecutive nodes of the displacement of air molecules?</h3>
  • Wavelength is the distance between two consecutive nodes or toughs or crests or anti-nodes.
  • So, distance between consecutive nodes = wavelength = 2π÷k

= 2π/(4π÷m)

= m/2

<h3>What's the amplitude after 0.56s of the displacement of air molecules?</h3>

Displacement after 0.56 s = 0.008×cos(50π×0.56s)

=1.75×10^(-4) m

Thus, we can conclude that the distance between consecutive nodes and displacement after 0.56 s are m/2 and 1.75×10^(-4) m respectively.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: The particle displacement y of air molecules due to a sound wave is given by y=0.008coswtsinkz where k=4π÷m and w=50π rads/s.

Calculate:

I) the distance between 2 consecutive nodes

ii) the amplitude after 0.565s

Learn more about the wavelength here:

brainly.com/question/10750459

#SPJ1

8 0
2 years ago
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