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Natasha2012 [34]
3 years ago
5

How to calculate the pH of NH4OH(0.1M)

Chemistry
1 answer:
anastassius [24]3 years ago
8 0
Answer is: pH of ammonium hydroxide is 11.13.
Chemical reaction of ammonium hydroxide in water: NH₄OH → NH₄⁺ + OH⁻<span>.
</span>

Kb(NH₄OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₄OH<span>) = 0.1 M.
c(NH</span>₄⁺) = c(OH⁻<span>) = x.
c(</span>NH₄OH<span>) = 0.1 M- x.
Kb = c(NH</span>₄⁺) · c(OH⁻) / c(NH₄OH<span>).
0,000018 = x² /  0.1 mol/L - x</span>.

Solve quadratic equation: x = c(OH⁻) = 0.00133 M.

pOH = -logc(OH⁻).

pOH = 2.87.

pH = 14 - 2.87.

pH = 11.13.


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