Answer:
The answer to your question is 16.7 g of Cr(CH₃COO)₃
Explanation:
Data
Concentration = 0.243 M
Volume = 300 ml
mass of Chromium (III) acetate = ?
Process
1.- Write the formula of the compound
Cr(CH₃COO)₃
2.- Calculate the molar mass of the compound
Cr(CH₃COO)₃ = 52 + (6 x 12) + (9 x 1) + (6 x 16)
= 52 + 72 + 9 + 96
= 229 g
3.- Determine the number of moles
Molarity = moles /volume
Moles = Molarity x volume
Moles = 0.243 x 0.300
Moles = 0.0729
4.- Calculate the grams of chromium (III) acetate
229 g ------------------ 1 mol
x ----------------- 0.0729 mol
x = (0.0729 x 229) /1
x = 16.7 g of Cr(CH₃COO)₃
1) carbon dioxide
2) dinitrogen trioxide
3)Selenium monochloride
4)xenon monofluoride
5) sulfur monobromide
Gas in a closed solid container obeys the law of Amonton.
Amontons's law states that the pressure of a given amount of gas is directly proportional to its absolute temperature, provided that the volume remain constant. Gas filled in a closed solid container obeys the Amontons's law.
In a closed solid container, the volume does not change as the temperature of the inside environment increases because there is no space for the gas molecules to expand so we can conclude that due to solid structure of the container, the pressure of the gas molecules does not change the volume of the gas.
Learn more: brainly.com/question/24915187
Given the following equation: I N2(g) + 3H2(g) → _2_NH3(e) a. ... Calculate the number of grams of NH3 produced by the reaction of 5.40 g of ... C. How many grams of nitrogen are needed to produce 15.3 g of NH3?
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