Answer:
76.25cm
Explanation:
38cm + 56cm +97cm +114cm = 305cm
305cm÷4 = 76.25cm
The wavelength of the radiation is 4.7 x 10⁻⁹ m
What is the Einstein's Formula for Energy?
The energy
E is given, from Einstein's formula, as:
E=h⋅ν
Where:
h=6.63×10⁻³⁴Js is Planck's constant;
ν is the frequency.
You can relate frequency and wavelength
λ through the speed of light c as:
c=λ⋅ν
So finally you get:
E=hc/λ
It is given in the question
The energy of a photon is 4.23 x 10⁻¹⁷ J.
Wavelength = ?
λ = hc/E
λ = 6.63×10⁻³⁴x 3 x 10⁸ / 4.23 x 10⁻¹⁷
λ = 4.7 x 10⁻⁹ m
Therefore the wavelength of the radiation is 4.7 x 10⁻⁹ m .
To know more about Einstein's Equation for Energy
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The solution for this problem is:
Let x = speed of wind
Speed of plane with the wind = x + 100
Speed of plane against the wind = 100 -x
We will be using the formula for distance which is (Rate)(Time), getting the formula for time would be distance/rate Time to travel 600 miles with the wind = Time to travel 400 miles against the wind 600/(x + 100) = 400/(100 - x)
400(x + 100) = 600(100 - x)
400x + 40000 = 60000 - 600x
1000x = 20000
x = 20000/1000
x = 20 mph
First, we need to get the concentration of [NaH2PO4]:
[NaH2PO4] =( mass / molar mass ) * volume L
when we have mass NaH2PO4 = 6.6 g & molar mass = 120g/mol & V = 0.355 L
So by substitution:
[NaH2PO4] = (6.6g / 120g/mol) * 0.355 L = 0.0195 M
then, we need to get the concentration of [Na2HPO4]:
[Na2HPO4]= (mass / molar mass ) * volume L
So by substitution:
[Na2HPO4] = (8g/ 142g/mol) * 0.355 L = 0.02 M
and when Pka of the 2nd ionization of phosphoric acid = 7.21
So by substitution in the following formula, we can get the PH:
PH = Pka + ㏒[A]/[AH]
∴PH = 7.21 + ㏒[0.02]/[0.0195]
∴ PH = 7.2
Answer:
Mg + O2 ---> MgO
Explanation: V2O5 + CaS → CaO + V2S5. 5V2O5 + 5CaS → 10CaO + 5V2S5. 3V2O5 + 3CaS → 3CaO + 3V2S5.
