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gtnhenbr [62]
3 years ago
12

Molecules involved in a chemical reaction must meet to react. What is this concept called?

Chemistry
1 answer:
svetlana [45]3 years ago
8 0
I am pretty sure it’s Collision theory
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Which of the following is a homogeneous mixture? a.sodium chloride b.oxygen c.salad d.salt water
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The mass of 40 mL of water is 40 grams. Since D = m/v and mL = cm3, the density of water is 1 g/cm3. Choose a volume between 1 and 100 mL. Use your graph to find the mass.
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3 years ago
A diprotic acid, H₂A, has Ka1 = 3.4 × 10⁻⁴ and Ka2 = 6.7 × 10⁻⁹. What is the pH of a 0.18 M solution of H₂A?
Tcecarenko [31]

Answer:

pH = 2.10

Explanation:

We name an acid as diprotic because it can release two protons:

H₂A  +  H₂O  ⇄  H₃O⁺   + HA⁻     Ka₁

HA⁻  +  H₂O  ⇄  H₃O⁺   + A⁻²      Ka₂

We propose the mass balance:

Analytical concentration = [H₂A] +  [HA⁻]  + [A⁻²]

As Ka₂ is so small, we avoid the [A⁻²] so:

0.18 M = [H₂A] +  [HA⁻]

But we can not avoid the HA⁻, because the Ka₁. Ka₁'s expression is:

Ka₁ = [H₃O⁺] . [HA⁻] / [H₂A]

We propose the charge balance:

[H₃O⁺] = [HA⁻] + [A⁻²] + [OH⁻]

As we did not consider the A⁻², we can miss the term and if

Kw = H⁺ . OH⁻

We replace Kw/H⁺ = OH⁻. So the new equation is:

[H₃O⁺] = [HA⁻] + Kw / [H₃O⁺]

The acid is so concentrated, so we can avoid the term with the Kw, so:

[H₃O⁺] = [HA⁻]

In the mass balance we would have:

0.18 M = [H₂A]

We replace at Ka₁

Ka₁ = [H₃O⁺] . [HA⁻] / [H₂A]

Ka1 . 0.18 / [H₃O⁺] = [HA⁻]

We replace at the charge balance:

[H₃O⁺] = Ka1 . 0.18 / [H₃O⁺]

[H₃O⁺]² = 3.4×10⁻⁴  . 0.18

[H₃O⁺] = √(3.4×10⁻⁴  . 0.18)

[H₃O⁺] = 7.82×10⁻³

- log [H₃O⁺] = pH → - log 7.82×10⁻³

pH = 2.10

5 0
3 years ago
Can you help me balance this​
Zepler [3.9K]

Balanced equation

Mg₃(PO₄)₂ + 2Al(NO₃)₃ → 3Mg(NO₃)₂ + 2AlPO₄

<h3>Further explanation</h3>

Given

Reaction

Mg3(PO4)2 + Al(NO3)3 → Mg(NO3)2 + AlPO4

Required

Balanced equation

Solution

Give a coefficient :

Mg₃(PO₄)₂ + aAl(NO₃)₃ → bMg(NO₃)₂ + cAlPO₄

Make an equation :

Mg, left = 3, right=b⇒b=3

P, left=2, right=c⇒c=2

Al, left=a, right=c⇒a=c⇒a=2

The reaction becomes :

Mg₃(PO₄)₂ + 2Al(NO₃)₃ → 3Mg(NO₃)₂ + 2AlPO₄

7 0
3 years ago
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