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LUCKY_DIMON [66]

3 years ago

8

Jesse has 200 peanut butter cups and she gives some of them to her friend. How many peanut butter cups did she give her friend?

She now has 101 peanut butter cups

1 answer:

pychu [463]3 years ago

3 0

Answer:

99 peanut butter

Explanation:

you minus 200 - 101 you get 99 peanut butter

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3 years ago

A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se

zheka24 [161]

Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, $\lambda = 1\ nC = 1\times 10^{- 9}\ C$

Charge density of rod 2, $\lambda = - 1\ nC = - 1\times 10^{- 9}\ C$

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

$\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}$

Also,

$\vec{E} = \frac{2K\lambda }{R}$ (1)

where

K = electrostatic constant = $\frac{1}{4\pi \epsilon_{o} R}$

R = Distance

$\lambda$ = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

$\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C$

$\vec{E} = 1800\ N/C$ (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

$\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C$

$\vec{E'} = 1800\ N/C$ (towards)

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$\vec{E_{net}} = 1800 + 1800 = 3600\ N/C$

7 0

3 years ago

A baseball bat balances 74.9 cm from one end. If an 0.560-kg glove is attached to that end, the balance point moves 25.3 cm towa

timurjin [86]

Answer:

The mass of the bat is 1.09 kg.

Explanation:

Given that,

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$C=\dfrac{MX+mx}{M+m}$

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3 0

3 years ago