Explanation:
It is given that, a batter hits a pop-up to a fielder 93 m away, range of the projectile, R = 93 m
The ball remains in the air for 5.4 s, the time of flight is 5.4 s
Time of flight : ![T=\dfrac{2v\sin\theta}{g}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2v%5Csin%5Ctheta%7D%7Bg%7D)
![5.4=\dfrac{2v\sin\theta}{g}\\\\v\sin\theta=\dfrac{5.4\times 9.8}{2}\\\\v\sin\theta=26.46](https://tex.z-dn.net/?f=5.4%3D%5Cdfrac%7B2v%5Csin%5Ctheta%7D%7Bg%7D%5C%5C%5C%5Cv%5Csin%5Ctheta%3D%5Cdfrac%7B5.4%5Ctimes%209.8%7D%7B2%7D%5C%5C%5C%5Cv%5Csin%5Ctheta%3D26.46)
Maximum height of the projectile : ![H=\dfrac{v^2\sin^2\theta}{2g}](https://tex.z-dn.net/?f=H%3D%5Cdfrac%7Bv%5E2%5Csin%5E2%5Ctheta%7D%7B2g%7D)
We need to find H.
So,
![H=\dfrac{(v\sin\theta)^2}{2g}\\\\H=\dfrac{(26.46)^2}{2\times 9.8}\\\\H=35.72\ m](https://tex.z-dn.net/?f=H%3D%5Cdfrac%7B%28v%5Csin%5Ctheta%29%5E2%7D%7B2g%7D%5C%5C%5C%5CH%3D%5Cdfrac%7B%2826.46%29%5E2%7D%7B2%5Ctimes%209.8%7D%5C%5C%5C%5CH%3D35.72%5C%20m)
So, it will rise to a height of 35.72 m.
explorer 1 .........................
It will not explode since the mass of the cotton balls is so low but rather will most likely break the lock and hinges and come out.
A quantity with only magnitude is called a scalar.
e.g. Distance