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LUCKY_DIMON [66]
3 years ago
8

Jesse has 200 peanut butter cups and she gives some of them to her friend. How many peanut butter cups did she give her friend?

She now has 101 peanut butter cups
Physics
1 answer:
pychu [463]3 years ago
3 0

Answer:

99 peanut butter

Explanation:

you minus 200 - 101 you get 99 peanut butter

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H<br>Ggghffyjfdudjhfhghggffghjjdxv
amid [387]

Answer:

H

Ggghffyjfdudjhfhghggffghjjdxv

Explanation: The law of copying

6 0
3 years ago
GIZMO
CaHeK987 [17]
It is A or D but I believe A
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3 years ago
Two metal spheres are hanging from nylon threads. When you bring the spheres close to each other, they tend to attract. Based on
Tamiku [17]

Explanation:

In the given question, the two metal spheres were hanged with the nylon thread.

When these two spheres were brought close together, they attracted each other. The attraction between these spheres is the result of the opposite charges between them.

The possible ways by which these two metal spheres can be charged are by induction that is touching the metal or by rubbing them.

During induction, the same charges are transferred to each sphere. In this case, either both the spheres will be negatively charged or positively charged.

It is not possible that after the sphere touch each other they will cling together because the same charge repels each other and during touching, if one sphere is neutral, then the charged one will transfer the same charge. And as we know that same charge repel each other therefore they will repel each other.

4 0
3 years ago
You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.
Radda [10]

Answer:

Explanation:

The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also<u> assuming level road</u>.

E = ½mv² = ½(1000)30² = 450,000 J

5 0
2 years ago
Two cars are moving towards each other and sound emitted by first car with real frequency of 3000 hertz is detected by a person
sertanlavr [38]

Answer:

 v ’= 21.44 m / s

Explanation:

This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s

           f ’= f (v + v₀) / (v-v_{s})

where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer

in this exercise both the source and the observer are moving, we will assume that both have the same speed,

                v₀ = v_{s} = v ’

we substitute

               f ’= f (v + v’) / (v - v ’)

               f ’/ f (v-v’) = v + v ’

               v (f ’/ f -1) = v’ (1 + f ’/ f)

               v ’= (f’ / f-1) / (1 + f ’/ f) v

               v ’= (f’-f) / (f + f’) v

let's calculate

                v ’= (3400 -3000) / (3000 +3400) 343

                v ’= 400/6400 343

                v ’= 21.44 m / s

3 0
2 years ago
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