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3 years ago

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What is the law of gravitation

1 answer:

tia_tia [17]3 years ago

4 0

Answer:

Newton's paw of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance in between them

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PLEASE HELP QUICK I NEED IT TO PASS

BlackZzzverrR [31]

Answer:

Explanation:

As the contour lines have roughly the same spacing but the actual topography is much steeper, the lines on the mountainous map represent a larger vertical spacing than the lines on the gradual hills.

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2 years ago

A 70-kg ice skater is standing still on the ice, when a friend tosses him a 10-kg ball that is traveling at +8 m/s. If he catche

Misha Larkins [42]

Answer:+1.25 m/s

Explanation:

Given

mass of ice skater M=70 kg

mass of ball m=10 kg

the initial velocity of the ball $u_1=+8\ m/s$

Conserving linear momentum

$M\times0+m\timesu_1=(M+m)v\quad \quad [v=\text{combined velocity of skater and ball}]$

$v=\dfrac{10\times10}{80}=+1.25\ m/s$

Therefore the velocity of the person holding the ball is 1.25 m/s

This collision represents the perfectly inelastic collision where particles stick together after the collision.

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2 years ago

A basketball player spins the ball with an angular acceleration of 10 rad/s2. What is the ball’s final angular velocity if the b

Lena [83]

Explanation:

It is given that,

The angular acceleration of the basketball, $\alpha=10\ rad/s^2$

Time taken, t = 3 seconds

We need to find the ball’s final angular velocity if the ball starts from rest. It can be calculated using definition of angular acceleration i.e.

$\alpha=\dfrac{\omega_f-\omega_i}{t}$

$\omega_i=0\ (rest)$

$\omega_f=\alpha t$

$\omega_f=10\ rad/s^2\times 3\ s$

$\omega=30\ rad/s$

So, the ball's final angular velocity is 30 rad/s. Hence, this is the required solution.

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2 years ago

Is Salad dressing a compound ??

olasank [31]

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3 years ago

Read 2 more answers

Physics Question: Determine the work that is being done by tension in pulling the box 193.0 cm along the table. Also determine t

lozanna [386]

1) The work done by tension is 12.0 J

2) The final speed of the box is 1.57 m/s

Explanation:

The work done by a force on an object is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement

$\theta$ is the angle between the direction of the force and of the displacement

For the box in this problem, we have:

F = 6.2 N is the force applied (the tension in the string)

d = 193.0 cm = 1.93 m is the displacement

$\theta=0$ assuming that the string is horizontal

Substituting, we find the work done by the tension:

$W=(6.2)(1.93)(cos 0)=12.0 J$

2)

In order to determine the final speed of the box, we need to determine its acceleration first.

Beside the tension, acting forward, the other force acting horizontally on the box is the force of friction, whose magnitude is

$F_f = \mu mg$

where

$\mu=0.16$ is the coefficient of friction

m = 2.8 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting,

$F_f = (0.16)(2.8)(9.8)=4.4 N$

Therefore, the net force on the box is

$F=6.2 N - 4.4 N = 1.8 N$

And the acceleration can be found by using Newton's second law:

$F=ma$

where

F = 1.8 N is the net force

m = 2.8 kg is the mass of the box

a is the acceleration

Solving for a,

$a=\frac{F}{m}=\frac{1.8}{2.8}=0.64 m/s^2$

Now we can finally find the final speed using the suvat equation:

$v^2-u^2=2as$

where

v is the final speed

u = 0 is the initial speed

$a=0.64 m/s^2$ is the acceleration

s = 1.93 m is the displacement

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0+2(0.64)(1.93)}=1.57 m/s$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

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3 years ago