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Alecsey [184]
3 years ago
10

Consider the previous situation. Under what condition would the acceleration of the center of mass be zero? Keep in mind that F1

x and F2x represent the components, of the corresponding forces. Consider the previous situation. Under what condition would the acceleration of the center of mass be zero? Keep in mind that and represent the components, of the corresponding forces. F1x=−F2x F1x=F2x m1=m2 m1≪m2
Physics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

a) m₁ = m₂  F₁ₓ = F₂ₓ

b) m₁ << m₂   F₂ₓ =0

Explanation:

This interesting exercise is unclear your statement, so that in a center of mass system has an acceleration of zero it is necessary that the sum of the forces on each axis is zero, to see this we write Newton's second law

     ∑ F = m a

for acceleration to be zero implies that the net force is zero.

we must write the expression for the center of mass

        x_{cm} = 1 / M (m₁ x₁ + m₂ x₂)

now let's use the derivatives

      a_{cm} = d² x_{cm}/dt² = 1 / M (m₁ a₁ + m₂a₂)

where M is the total mass M = m₁ + m₂

     so that the acceleration of the center of mass is zero

               0 = 1 / M (m₁ a₁ + m₂a₂)

               m₁ a₁ = - m₂ a₂

In the case that we have components on the x axis, the modulus of the two forces are equal and their direction is opposite, therefore

   F₁ₓ = -F₂ₓ

b)r when the two masses are equal , in the case of a mass greater than the other m₁ << m₂

      acm = d2 xcm / dt2 = 1 / M (m1 a1 + m2a2)

so that the acceleration of the center of mass is zero

               0 = 1 / M (m1 a1 + m2a2)

               m1 a1 = - m 2 a2

with the initial condition, we can despise m₁, therefore

                0 = m₂a₂

 if we use Newton's second law

              F₂ = 0

       

I tell you that in this case with a very high mass difference the force on the largest mass must be almost zero

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Answer:

Approximately 72.9\; \rm m, assuming that the rocket had no propulsion onboard, and that air resistance on the rocket is negligible.

Explanation:

Initial velocity of this rocket: u = 27\; \rm m\cdot s^{-1}.

When the rocket is at its maximum height, the velocity of the rocket would be equal to 0. That is: v = 0\; \rm m \cdot s^{-1}.  

The acceleration of the rocket (because of gravity) is constantly downwards, with a value of a = -g = -10\; \rm m \cdot s^{-2}.

Let x denote the distance that the rocket travelled from the launch site to the place where it attained maximum height. The following equation would relate x \! to u, v, and a:

\displaystyle x = \frac{v^2 - u^2}{2\, a}.

Apply this equation to find the value of x:

\begin{aligned} x &= \frac{v^2 - u^2}{2\, a} \\ &= \frac{\left(0\; \rm m\cdot s^{-1}\right)^{2} - \left(27\; \rm m \cdot s^{-1}\right)^{2}}{2 \times 10\; \rm m \cdot s^{-2}} = 36.45\; \rm m\end{aligned}.

In other words, the maximum height that this rocket attained would be 36.45\; \rm m.

Again, assume that the air resistance on this rocket is negligible. The rocket would return to the ground along the same path, and would cover a total distance of 2\times 36.45\; \rm m = 72.9\; \rm m.

7 0
3 years ago
(a) Calculate the tension in a vertical strand of spiderweb if a spider of mass 5.00 ✕ 10-5 kg hangs motionless on it.
sertanlavr [38]

a)The tension in the vertical strand will be 0.00049 N.

b))The tension in the horizontal strand will be 0.001284 N.

c)The ratio of tension in the horizontal strand to the tension in the vertical strand will be  2.62.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given data;

Mass of spiderweb = 5.00 ✕ 10⁻⁵ kg

The tension in a horizontal strand of a spiderweb, Tₓ

The tension in a  vertical strand of a spiderweb, Tₐ

The angle at which the strand sags, Θ = 10.0°

R is the ratio of  tension in the horizontal strand to the tension in the vertical strand

a)

From the FBD,

The tension  in the vertical strand is equal to the weight of the spider;

Tₐ = W

Tₐ = mg

Tₐ= 5 x 10⁻⁵ kg x 9.8 m / s²

Tₐ= 0.00049 N.

(b)

The super's total vertical forces are zero since it is not moving the value of the tension in the horizontal strand;

Tₓ = mg/( 2sinΘ)

Tₓ = 5 x 10⁻⁵ kg x 9.8 m /s² / ( 2 sin 11° )

Tₓ= 0.001284 N.

c)

R is the tension in the vertical strand divided by the tension in the horizontal strand.

R= Tₐ / Tₓ

R= 0.001284 N / 0.00049 N

R= 2.62

Hence, the tension in a vertical strand of a spiderweb, the tension in a horizontal strand of a spiderweb, and the ratio of tension in the horizontal strand to the tension in the vertical strand will be 0.00049 N, 0.001284 N, and 2.62 respectively.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

#SPJ1

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2 years ago
The graph below represents the relationship between speed and time for an object moving along a straight line. What is the total
KiRa [710]

The distance travelled by the object during the first 4 seconds is 80 m

<h3>Definition of speed </h3>

Speed is defined as the distance travelled per unit time. Mathematically, it can be expressed as:

Speed = distance / time

With the above formula, we can obtain the distance travelled by the object in the first 4 seconds.

<h3>How to determine the distance travelled </h3>
  • Speed = 20 m/s
  • Time = 4 s
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Speed = distance / time

20 = distance / 4

Cross multiply

Distance = 20 × 4

Distance = 80 m

Complete question:

See attached photo

Learn more about speed:

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Answer:

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Explanation:

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