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Karo-lina-s [1.5K]
3 years ago
12

An object with a temperature of 0 Kelvin would not emit radiation. a. True b. False

Physics
2 answers:
dem82 [27]3 years ago
5 0
That's true. 
Radiation always carries energy. 
An object at 0 K doesn't have any.
kow [346]3 years ago
4 0

Answer: TRUE

Explanation:

this answer is tested by me. i answered true in my quiz and it was correct.

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A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is
Vikki [24]

Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

6 0
2 years ago
The ray model of light states that light travels in the form of ?
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Electromagnetic waves
4 0
3 years ago
juan aims his boat directly across a river flowing at 8mi/hr. juan's boat travels at 6 miles/hr in still water. how was does jua
son4ous [18]
6mph:

Suppose the boat is traveling on a y axis. The river flow acts on the x axis. Motion on each axes are independent. The linear speed of the boat is not changed. Furthermore the projectile motion is changing, but you're specifically asking about the linear speed of the boat which is unchanged.
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3. A block falls from a table 0.6 m high. It lands on a vertical spring which has a spring constant of k= 2400 N/m.
goldfiish [28.3K]
<h2>SOLUTION :-</h2>
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8 0
2 years ago
Calculate the energy per photon and the energy per mole of photons for radiation of wavelength (a) 200 nm (ultraviolet), (b) 150
VMariaS [17]

Answer: a. E =9.9*EXP(-19)J

1 mole E= 596178J

b. E= 1.32*EXP(-15)J, 1 mole E=795MegaJ

c. E= 1.98*EXP(-23)J

1 mole E = 11.9J

Explanation: The Energy of a photon E, the wavelength are related by

E= h*c/wavelength

h is the Planck's constant 6.6*EXP(-34)J.s

c is speed of light 3*EXP(8)m/s

h*c=1.98*EXP(-25)

Now let's solve

a. E = h*c/wavelength

= h*c/(200*EXP(-9)m

=9.9*EXP(-19)J

1 mole of a photon contian 6.022*EXP(23)photons by advogadro

Now to get the energy of 1 mole of the photon we have

9.9*EXP(-19)*6.023*EXP(23)

=596178J

b. E=h*c/150*EXP(-12)m

=1.32*EXP(-15)J

1 mole will have

1.32*EXP(-15)*6.022*EXP(23)J

=795*EXP(6)J

c. E= h*c/1*EXP(-2)m

=1.98*EXP(-23)J

1 mole of the photon will have

1.98*EXP(-23)J *6.022*EXP(23)

= 11.9J.

You will notice that the longer the wavelength of the photon the lesser the Energy it as.

NOTE: EXP represent 10^

8 0
4 years ago
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