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3 years ago

An object with a temperature of 0 Kelvin would not emit radiation. a. True b. False

Physics

2 answers:

dem82 [27]3 years ago

5 0

That's true.
Radiation always carries energy.
An object at 0 K doesn't have any.

kow [346]3 years ago

4 0

Answer: TRUE

Explanation:

this answer is tested by me. i answered true in my quiz and it was correct.

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n general, which trophic level has the LEAST energy available to it? A) producer B) primary consumer C) secondary consumer D) te

zaharov [31]

D - tertiary consumer

This is because it is the farther up to food chain.

4 0

3 years ago

Question 6 (2 points)

LenKa [72]

Answer:

A. increase the speed

Explanation:

For you to be able to shorten the time it takes for the care to get to its destination, you must increase the speed because if the distance is the same that means you have to increase your speed.

3 0

3 years ago

A. 7cm<br>B. 24cm<br>C. 18cm<br>D. 63cm

Alex17521 [72]

Answer:

A. 7cm

I hope it helps...

6 0

3 years ago

Sherlock Holmes examines a clue by holding his magnifying glass (with

Alborosie

Answer:

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

$\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm$

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

$M=-\frac{q}{p}=-\frac{-30}{10}=3$

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

8 0

4 years ago

A small block slides down an incline with a constant acceleration. The block is released from rest at the top of the incline. Af

zloy xaker [14]

Answer:

v = 3.24 m/s

Explanation:

Since we don't have time, we can use the formula;

(Final distance - initial distance)/time = (initial velocity + final velocity)/2

Thus;

(x_f - x_i)/t = ½(v_xi + v_xf)

We are given;

x_i = 0 m

x_f = 5 m

v_xi = 0 m/s

v_xf = 5 m/s

Thus, plugging in the relevant values;

(5 - 0)/t = (0 + 5)/2

5/t = 5/2

t = 2 s

Using Newton's first law of motion, we can find the acceleration.

v = u + at

Applying to this question;

5 = 0 + a(2)

5 = 2a

a = 5/2

a = 2.5 m/s²

To get the speed, in m/s, of the block when it had traveled only 2.1 m from the top, we will use the formula;

v² = u² + 2as

v² = 0² + 2(2.5 × 2.1)

v² = 10.5

v = √10.5

v = 3.24 m/s

3 0

4 years ago