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coldgirl [10]
2 years ago
9

The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:

Chemistry
1 answer:
motikmotik2 years ago
4 0

The allowable combination for the atomic orbital is n=3, l=1, m_{l}=-1.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 3, l can have three values: 0, 1, and 2. Since m_{l} values are integers from -l to 0 to +l, for l = 0 the value of m_{l} cannot be -1 (l = 0 has m_{l}= 0).

There are two l values that are consistent with n and m_{l} values:

l=1 or 2

Therefore, the allowable condition is n=3, l=1, m_{l}=-1.

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

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Perform the following
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Answer:

8.73

Explanation:

when you are adding or subtracting numbers, the sigfig (significant figure) is based on how many numbers after the decimal. with this info, we can see that 15.67 has 2 sigfigs and 6.943 has 3 sigfigs. when you subtract normally, you would get 8.727, which has 3 sigfigs, so you would round the last 7 up to get 8.73 with 2 sigfigs!

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3 years ago
A chemist lectures about the following definition for acids and bases. The acid-base behavior is analyzed in terms of how electr
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What orbits from a pi bond
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4 0
3 years ago
Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the boiling of water, and exp
Sedbober [7]

Answer:

ΔH > 0; ΔS >0; ΔG = 0

Not spontaneous when T < 100 °C;

         Equilibrium when T = 100 °C

      Spontaneous when T > 100 °C

Step-by-step explanation:

The process is

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ΔH > 0 (positive), because we must <em>add heat</em> to boil water

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If T < 100 °C, the ΔH term will predominate, because T has decreased below the equilibrium value.

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ΔG < 0. The process is spontaneous above 100 °C.

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