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Andrej [43]
1 year ago
13

A proton is held at rest in a uniform electric field. When it is released, the proton will lose?

Physics
1 answer:
nydimaria [60]1 year ago
5 0

A proton is held at rest in a uniform electric field. When it is released, the proton will lose its kinetic energy.

Kinetic energy

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.

To learn more about kinetic energy refer here:

brainly.com/question/11301578

#SPJ4

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Power can be defined as?
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B. How much work can be done in a given time. That’s why it’s measured occasionally I. “Horsepower.” It’s your ability to work fast and far.
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3 years ago
In case of collision of objects in two dimensions which statement is true after the collision?
Grace [21]

The correct answer to the question is : C) The horizontal momentum and the vertical momentum are both conserved. 

EXPLANATION :

Before coming into any conclusion, first we have to understand the law of conservation of momentum.

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Hence, the total horizontal momentum as well as total vertical momentum are always conserved during both elastic as well as inelastic collision.



5 0
3 years ago
Read 2 more answers
The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?
Aloiza [94]

Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

6 0
3 years ago
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If you pull on something to the right with a force of 50 N and I pull on the same object to the left with a force of 60 N, what
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Nxxncnx. NMakalsllalakskdnd cxhcnmdnx
7 0
3 years ago
25 PTS
yarga [219]
The answer would be C
7 0
3 years ago
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