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agasfer [191]
3 years ago
14

0. When measuring tert-butyl alcohol for this experiment, a student first weighs an empty graduated cylinder, then pours 15 mL o

f the alcohol into the graduated cylinder and weighs the cylinder again. He records the amount of alcohol used as the difference in these two masses. What is wrong with this method
Chemistry
1 answer:
lozanna [386]3 years ago
6 0

Answer:

Both have solutions in the  graduated cylinder.

Explanation:

Recording the amount of alcohol used as the difference between two masses is the wrong method used for measuring tert-butyl alcohol for the experiment.  For measuring tert-butyl alcohol for this experiment, the student has to measure the two masses when both the graduated cylinders has solution of tert-butyl alcohol not when one of it is empty (having no tert-butyl alcohol ).

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Oxycodone (C18H21NO4), a narcotic analgesic, is a weak base with pKb = 5.47. Calculate the pH of a .00500 M oxycodone solution.
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Answer:

pH = 10.11

Explanation:

Hello there!

In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:

C_{18}H_{21}NO_4+H_2O\rightleftharpoons C_{18}H_{21}NO_4H^+OH^-

We can therefore set up the corresponding equilibrium expression:

Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}

Which can be written in terms of the reaction extent, x:

Kb=\frac{x^2}{0.00500M-x}=3.39x10^{-6}

Thus, by solving for x we obtain:

x_1=-0.000132M\\\\x_2=0.0001285M

However, since negative solutions are now allowed, we infer the correct x is 0.0001285 M; thus, the pOH can be computed:

pOH=-log(x)=-log(0.0001285)=3.89

And finally the pH:

pH=14-pOH=14-3.89\\\\pH=10.11

Best regards!

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