P2 = 54.6 kPa
Explanation:
Given:
V1 = 10.0 L. V2 = 50.0 L
P1 = 273 kPa. P2 = ?
We can use Boyle's law to solve this problem.
P1V1 = P2V2
Solving for P2,
P2 = (V1/V2)P1
= (10.0 L/50.0 L)(273 kPa)
= 54.6 kPa
<span>The ammonia molecules have weaker inter molecular bonds then the hydrogen and nitrogen, this means that the ammonia condensed at a lower temperature so will be a liquid that will be separated from the reaction, while the nitrogen and hydrogen remain as gases so are easy are recycle back into the reacting chamber.</span>
Answer:
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
Explanation:
The Bold Numbers are what you should put. This is balanced
Whichever one has a negative enthalpy value.
Answer:
A 25% of the initial parent nuclei.
Explanation:
One half life, you get 50%, two half lives you get 25% and you just keep dividing by 2 from there. :) Good luck my friend!
