Answer:
a = = 37.2V
b = 13.39MJ
Explanation:
Given that
L = 170 × 10³
r = d/2
= 10cm / 2 = 5 cm
current I = 100A
we are to find the potential drop across the cable
so, we can use ohm’s law
V = IR = I (ρL/A)
ρ = resistivity of the copper
= 1.72 × 10⁻⁸ Ω.m
A = πr²
V = I(ρL/πr²)
= 100 (( 1.72 × 10⁻⁸ * 170 × 10³) / ( π * 0.05²))
= 37.2V
(b)
Energy (loss) = Pt
Enery (loss) = IVt
3600s per hour
= (100A)(37.2V)(3600s)
= 13.39MJ
Derived Units Table: The Table Shows the List of Derived Units
Quantity Formula SI Derived Unit
Force Mass x Acceleration
Work Energy Force x Displacement Power/Time Kg. m.s-2
Pressure, Stress Force/Area Kg.m-1.s-2
Current density J = I/A A.m-2
Answer:
Explanation:
The minimum total work is the work needed to counteract the work associated with the weight:
Answer:
theoretically speaking I don't even wanna believe it's possible but if it does then then you should check for abortion
