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3 years ago

What is the molecular formula if the empirical formula is CH20 and the molecular

Chemistry

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

Answer:

The molecular formula of the given compound is C6H12O6, which is also called Glucose.

Explanation:

The molar mass of glucose is 180.18.

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Use Boyle’s law to complete the following:

mixas84 [53]

Answer:

The answer to your question is: 0.25 l

Explanation:

Data

P1 = 1 atm

V1 = 0.5 l

P2 =2 atm

V2 = ?

T = constant

Formula

V1P1 = V2P2

Clear V2 from the formula

V2 = V1P1/P2

Substitution

V2 = (0.5)(1)/2 substitution

= 0.25 l result

3 0

3 years ago

Will give brainliest!!!!

Alekssandra [29.7K]

Answer:

Its B :)

Hope this helps

7 0

3 years ago

How many moles (of molecules or formula units) are in each sample?

Alexus [3.1K]

The number of moles in each sample will be 0.391 moles, 30.7 moles, 0.456 moles, and 1350 moles

<h3>What is the number of moles?</h3>

The number of moles of a substance is the ratio of the mass of the substance to the molar mass.

In other words; mole = mass/molar mass.

Thus:

moles of 18.0 g $NO_2$ = 18.0/46

= 0.391 moles

moles of 1.35 kg $CO_2$ = 1350/44

= 30.7 moles

moles of 46.1 g $KNO_3$ = 46.1/101.1

= 0.456 moles

moles of 191.8 kg $Na_2SO_4$ = 191800/142

= 1350 moles

More on the number of moles of substances can be found here: brainly.com/question/1445383

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5 0

2 years ago

Calculate the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 ml solution.

Lelechka [254]

Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity in this case</h3>

In this case, you have:

number of moles= 0.2 moles
volume= 100 mL= 0.1 L

Replacing in the definition of molarity:

$molarity=\frac{0.2 mole}{0.1 L}$

Solving:

<u><em>molarity= 2 </em></u> $\frac{moles}{liter}$

Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2 $\frac{moles}{liter}$ .

Learn more about molarity:

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8 0

2 years ago

identify the reagents you would use to convert each of the following compounds into pentanoic acid: (a) 1-pentene (b) 1-bromobut

Morgarella [4.7K]

a)BH3.THF is used to convert 1-pentane to pentanoic acid and b)NaCN is used to convert Bromobutane to pentanoic acid.

a) The conversion of 1-pentane to pentanoic acid using BH3, also known as hydroboration-oxidation, is a two-step reaction involving the reaction of 1-pentane with borane (BH3), followed by oxidation of the resulting 1-pentylborane with hydrogen peroxide or other oxidizing agents.

In the first step, 1-pentane reacts with borane (BH3) to form 1-pentylborane, through a process known as hydroboration. This reaction is catalyzed by a Lewis acid, such as aluminum chloride, and proceeds via a hydride transfer from the borane to the 1-pentane.

In the second step, the 1-pentylborane is oxidized to pentanoic acid using hydrogen peroxide (H₂O₂) or other suitable oxidizing agents. The oxidation is catalyzed by an acid, such as hydrochloric acid (HCl), and proceeds via a proton transfer from the 1-pentylborane to the hydrogen peroxide. The end result is the conversion of 1-pentane to pentanoic acid.

The overall chemical reaction for the conversion of 1-pentane to pentanoic acid using borane (BH₃) and hydrogen peroxide (H₂O₂) is as follows:

1-pentane + BH₃ + H₂O₂ → pentanoic acid + H₂O + BH₂

b)The conversion of 1-Bromo butane to pentanoic acid using sodium cyanide (NaCN) proceeds via a nucleophilic substitution reaction. The reaction mechanism involves the following steps:

1. Attack of the nucleophile, NaCN, on the carbon atom of 1-Bromo butane to form a tetrahedral intermediate.

2. Loss of a proton from the tetrahedral intermediate to form a carbanion.

3. Protonation of the carbanion by water (or another proton source) to form pentanoic acid.

The overall reaction can be represented as follows:

1-Bromo butane + NaCN → Pentanoic Acid + NaBr

To know more about reagents, click below:

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3 0

1 year ago