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ziro4ka [17]
2 years ago
11

Four cups of pure water are added to a 20-cup bowl of punch that is 75% juice. What percentage of the new punch is juice? Origin

al (Cups) Added (Cups) New (Cups) Amount of Juice 15 0 Amount of Punch 20 4 27% 37. 5% 62. 5% 75%.
Chemistry
1 answer:
zepelin [54]2 years ago
4 0

Based on the information given the percentage of the new punch is juice is 62.5%.

<h3>Percentage of new punch:</h3>

First step is to calculate how many cups of juice will a 20-cup bowl of punch have:

Number of cups=0.75×20

Number of cups= 15 cups  

Second step is to calculate the percentage of the new punch

Percentage=Number of cups/Total new punch number of cups

Percentage=15/24×100

Percentage=62.5%

Inconclusion  the percentage of the new punch is juice is 62.5%.

Learn more about percentage of new punch here:brainly.com/question/1446633

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NikAS [45]

Answer:

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6 0
2 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0
3 years ago
A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.9
Ronch [10]

Answer:

The free energy = -20.46 KJ

Explanation:

given Data:

Pb²⁺ = 0.750 M

Br⁻ = 0.232 M

R = 8.314 Jk⁻¹mol⁻¹

T = 298K

The Gibb's free energy is calculated using the formula;

ΔG = ΔG° + RTlnQ -------------------------1

Where;

ΔG° = standard Gibb's freeenergy

R = Gas constant

Q = reaction quotient

T = temperature

The chemical reaction is given as;

Pb²⁺(aq) + 2Br⁻(aq) ⇄PbBr₂(s)

The ΔG°f are given as:

ΔG°f (PbBr₂)  = -260.75 kj.mol⁻¹

ΔG°f (Pb²⁺)   = -24.4 kj.mol⁻¹

ΔG°f (2Br⁻)    = -103.97 kj.mol⁻¹

Calculating the standard gibb's free energy using the formula;

ΔG° = ξnpΔG°(product) - ξnrΔG°(reactant)

Substituting, we have;

ΔG° =[1mol*ΔG°f (PbBr₂)] - [1 mol *ΔG°f (Pb²⁺) +2mol *ΔG°f (2Br⁻)]

ΔG° =(1 *-260.75 kj.mol⁻¹) - (1* -24.4 kj.mol⁻¹) +(2*-103.97 kj.mol⁻¹)

      = -260.75 + 232.34

     = -28.41 kj

Calculating the reaction quotient Q using the formula;

Q = 1/[Pb²⁺ *(Br⁻)²]

   = 1/(0.750 * 0.232²)

  = 24.77

Substituting all the calculated values into equation 1, we have

ΔG = ΔG° + RTlnQ

ΔG = -28.41 + (8.414*10⁻³ * 298 * In 24.77)

     = -28.41 +7.95

    = -20. 46 kJ

Therefore, the free energy of reaction = -20.46 kJ

8 0
2 years ago
Water exhibits high levels of cohesion due to the polarity of the molecule (positively and negatively charged sides). given this
nalin [4]
Covalent bonds and it is between the hydrogens (hydrogen bonds)
7 0
3 years ago
Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.
dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0
2 years ago
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