Answer:
The tension in the rod as the ball moves through the bottom circle is 9.8 N
Explanation:
When the ball is released from rest, the centripetal force equals the weight of the ball. So mv²/r = mg where m = mass of ball = 0.5 kg, v = speed of ball, r = radius of vertical circle = length of rod = 0.5 m and g = acceleration due to gravity = 9.8 m/s²
v = √gr = √9.8 m/s² × 0.5 m = √4.9 = 2.21 m/s
Now at the bottom of the circle T - mg = mv²/r where T = tension in the rod
T = m(g + v²/r)
= m(g + (√gr)²/r)
= m(g+ gr/r)
= m(g + g)
= 2mg
= 2 × 0.5 kg × 9.8 m/s²
= 9.8 N
So, the tension in the rod as the ball moves through the bottom circle is 9.8 N
To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.
By definition we know that the relative velocity of an object with reference to the Light, is defined by

Where,
V = Speed from relative point
c = Speed of light
On the other hand we have that the linear momentum is defined as
P = mv
Replacing the relative velocity equation here we have to







Therefore the height with respect the observer is



Therefore the height which the observerd measure for her is 0.56m
Answer:
The value is
Explanation:
From the question we are told that
The mass is
The needed oscillation time is
Generally the spring constant is mathematically represented as

=> 
=>
A lot of it is all experimental as long as you are taking caution of safety while doing it. I personally would use copper wiring mainly for the fact that it is a nice conductor. For the wrap around the wiring i usually would use black or red electrical tape just because it has very nice insulator properties and is safe to use.
Answer:

Explanation:
given,
radius of circle = 1.8 m
mass of the ball = 0.1 Kg
linear speed of the ball = 27 m/s
angular velocity of orbit = ?
ω is the angular speed of the circle
the angular velocity of the orbit is 