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dalvyx [7]
3 years ago
9

A car is traveling on the highway at 28 m/s The driver sees a tree in the middle of the road and slams on the brakes. The car co

mes to a complete stop over a distance of 35 meters. What was the acceleration of the car as it was coming to a stop?
Physics
1 answer:
wel3 years ago
3 0

Answer:what are the answer options?

Explanation

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Biology. The science of all living creatures
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True or false Plant cells and animal cells have all the same major parts
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Flase plant cells and animals cells have almost the same major parts but some parts are different or in different places
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An automobile with a mass of 1165 kg accelerates at a rate of 5 m/s² in the forward direction. What is the net force acting on t
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3 years ago
A car moves with a speed of 72 km/h for 15 minutes and then with a speed of 80 km/h for the next 12 minutes. The total distance
sukhopar [10]

Answer:

The total distance covered by the car is 3,810.08 m

Explanation:

Given;

initial speed of the car, u = 72 km/hr = 20 m/s

initial time, t₁ = 15 minutes = 900 s

final speed of the car, v = 80 km/hr = 22.22 m/s

final time, t₂ = 12 minutes = 720 s

The acceleration of the car is given as;

a = \frac{v-u}{t_2 -t_1} \\\\a = \frac{22.22-20}{900-720}\\\\a = 0.0123 \ m/s^2

The total distance covered by the car is given as;

v² = u² + 2as

where;

s is the total distance covered by the car

22.22² = 20² + 2(0.0123)s

22.22²  - 20² = 2(0.0123)s

93.728 = 0.0246s

s = 93.728 / 0.0246

s = 3,810.08 m

Therefore, the total distance covered by the car is 3,810.08 m

8 0
3 years ago
Read 2 more answers
a student lift a 25kg mass at vertical distance of 1.6m in a time of 2.0 seconds. a. Find the force needed to lift the mass (in
zhannawk [14.2K]

Answer:

a. F = 245 Newton.

b. Workdone = 392 Joules.

c. Power = 196 Watts

Explanation:

Given the following data;

Mass = 25kg

Distance = 1.6m

Time = 2secs

a. To find the force needed to lift the mass (in N );

Force = mass * acceleration

We know that acceleration due to gravity is equal to 9.8

F = 25*9.8

F = 245N

b. To find the work done by the student (in J);

Workdone = force * distance

Workdone = 245 * 1.6

Workdone = 392 Joules.

c. To find the power exerted by the student (in W);

Power = workdone/time

Power = 392/2

Power = 196 Watts.

5 0
3 years ago
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