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kolbaska11 [484]
3 years ago
10

One of the most worrisome waste products of a nuclear reactor is plutonium

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0
One of the most worrisome waste products of a nuclear reactor is plutonium 239 (239Pu). This nucleus is radioactive and decays by splitting into a helium-4 nucleus and a uranium-235 nucleus (4He +... Q: One of the most worrisome waste products of a nuclear reactor is plutonium 239 (239Pu<span>).</span>
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How much heat is required to change temperature of 2g of water from 34°C to 68°C? (Water has a specific heat of 4.18)
statuscvo [17]

Answer: B

Explanation:

To find the amount of heat required, you would use q=mcΔT.

q=2g(4.18J/g°C)(68-34°C)

q=284.2 J

*Please ignore the capital A in the equation. I can't find a way to type in the degree sign into the equation without the A appearing.

4 0
3 years ago
Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

Best regards!

5 0
2 years ago
According to the ph scale, what is the approximate ph of ammonia solution?
UNO [17]
I believe that the answer is 11.5
5 0
3 years ago
A lead ball is added to a graduated cylinder containing 50.6 ml of water, causing the level of the water to increase to 93.0 mL.
Kamila [148]

42.4 ml is the volume in milliliters of the lead ball if a lead ball is added to a graduated cylinder containing 50.6 ml of water.

<h3>What is a graduated cylinder?</h3>

A tall narrow container with a volume scale is used especially for measuring liquids.

The graduated cylinder contains water

mL is a volume unit.

Water volume = 50.6 ml

The lead ball caused an increase in volume from 50.6 ml to 93.0 mL.

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

93.0 mL= V_(lead ball) +50.6 ml

V_(lead ball) = 93.0 mL - 50.6 ml

V_(lead ball) = 42.4 ml

Hence, 42.4 ml is the volume in milliliters of the lead ball.

Learn more about the graduated cylinder  here:

brainly.com/question/13386106

#SPJ1

4 0
2 years ago
A mixture of compounds containing diethylamine, phenol, ammonia, and acetic acid is separated using liquid-liquid extraction as
umka2103 [35]

Answer:

I would expect to extract the acetic acid.

Explanation:

In the first step, since we are adding a concentrated acid,<u> it will react with the bases present in the mixture (diethylamine and ammonia) </u><u>forming salts</u><u>, </u><u>which are soluble in water</u>. Therefore, after draining the aqueous layer, we will have phenol and acetic acid left in the organic layer.

In the second step, we are adding a diluted base, so it will react with a strong acid. This compound is acetic acid, and its salt will be present in the aqueous layer. Phenol will be left on the organic layer.

7 0
3 years ago
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