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Alla [95]
3 years ago
12

While working in the lab, you observe the following volume.

Chemistry
2 answers:
MakcuM [25]3 years ago
7 0

Answer:

B 18.4L

Explanation:

sp2606 [1]3 years ago
3 0

Answer:

The answer is 18.4 mL

The liquid is between 19 and 17

so the answer will be 18.4 mL

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Mashutka [201]

Newton's first law of motion predicts the behavior of objects where all existing forces are balanced. Objects at equilibrium will not accelerate. Also, an object will only accelerate if there is a net or unbalanced force acting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.

Newton's second law of motion: behavior of objects for and all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object  is increased, the acceleration of the object is decreased.

8 0
3 years ago
Which step do you use first to calculate the number of grams of FeCl2 produced when starting with 30.3 g of Fe in this reaction?
Lisa [10]

Answer:

I dont care I want pionts

5 0
3 years ago
In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th
Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

4 0
3 years ago
How many moles of h2 can be formed if a 3.25g sample of Mg reacts with excess HCl
kogti [31]

Answer:

0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles react:

  • Mg: 1 mole
  • HCl: 2 moles
  • MgCl₂: 1 mole
  • H₂: 1 mole

Being:

  • Mg: 24. 31 g/mole
  • H: 1 g/mole
  • Cl: 35.45 g/mole

the molar mass of the compounds participating in the reaction is:

  • Mg: 24.31 g/mole
  • HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
  • MgCl₂: 24.31 g/mole + 2*35.45 g/mole= 95.21 g/mole
  • H₂: 2*1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following quantities of mass participate in the reaction:

  • Mg: 1 mole* 24.31 g/mole= 24.31 g
  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • MgCl₂: 1 mole* 95.21 g/mole= 95.21 g
  • H₂: 1 mole* 2 g/mole= 2 g

Then you can apply the following rule of three: if by stoichiometry 24.31 grams of Mg form 1 mole of H₂, 3.25 grams of Mg how many moles of H₂ will they form?

moles of H_{2} =\frac{3.25 grams of Mg*1 mole of H_{2} }{24.31 grams of Mg}

moles of H₂= 0.134

<u><em>0.134 moles of H₂ can be formed if a 3.25g sample of Mg reacts with excess HCl</em></u>

7 0
4 years ago
jason and manuel wanted to separate sand from water in the space provided draw the set up required to obtain water from such a m
yuradex [85]

Answer:

here is the answer, hope this helped!

5 0
2 years ago
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