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Alla [95]
2 years ago
12

While working in the lab, you observe the following volume.

Chemistry
2 answers:
MakcuM [25]2 years ago
7 0

Answer:

B 18.4L

Explanation:

sp2606 [1]2 years ago
3 0

Answer:

The answer is 18.4 mL

The liquid is between 19 and 17

so the answer will be 18.4 mL

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A spring requires a force of 25 n to produce an extension of 2 cm in it. what is the work done in further extending it by 3 cm
Sonbull [250]
The force of a spring can be calculated by the expression:

F = kx  where k is a constant and x is the distance.

From the problem statement, we can solve the value of k from the initial conditions given as F = 25 N and x = 2 cm.

25 = k (0.02)
k = 1250

We use the work formula which is force times the distance resulting to the expression:

W = (1/2)(kx^2)
W = (1/2)(1250)(0.03^2)
W = 0.5625 J
4 0
3 years ago
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Where is the air pressure greater-- at sea level or on a mountaintop? Explain
Nady [450]

Answer:

Air pressure is greater at sea level than at the top of a mountain. The amount of air at sea level is greater than that on top of a mountain.

Explanation:

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8 0
2 years ago
A 40.4 g sample of a protein contains 17.16 g of carbon, 3.17 g of hydrogen, 13.71 g of oxygen, and the rest being nitrogen. Thi
lukranit [14]
<h3>The molecular formula of this protein : C₁₈H₄₂O₁₂N₆</h3><h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

The principle of determining empirical formula and molecular formula  

  • Determine the mass ratio of the constituent elements of the compound.  
  • Determine the mole ratio by dividing the elemental mass with the relative atomic mass obtained by the empirical formula  
  • Determine molecular formulas by looking for values of n  

Find mol ratio for every component :

  • C (Ar=12 g/mol):

\tt \dfrac{17.16}{12}=1.43

  • H(Ar=1 g/mol) :

\tt \dfrac{3.17}{1}=3.17

  • O(Ar=16 g/mol) :

\tt \dfrac{13.71}{16}=0.857

N (r=14 g/mol) :

Mass of Nitrogen :

40.4-(17.16+3.17+13.71)=6.36 g

  • N :

\tt \dfrac{6.36}{14}=0.454

C : H : O : N = 1.43 : 3.17 : 0.857 : 0.454 = 3.15 : 7 : 1.89 : 1=3:7:2:1

Empirical formula : C₃H₇O₂N

Molecular mass of protein :

\tt \dfrac{40.4}{0.07141}=565.75

(C₃H₇O₂N)n=565.75

(12.3+1.7+2.16+14)n=565.75

(89)n=565.75

n=6.4≈6

so the molecular formula : C₁₈H₄₂O₁₂N₆

6 0
2 years ago
PLEASE HELP !!!!!!!!!!!!! 20 POINTS Give two examples of elements and two examples of compounds. (4 points) 16. Consider a hypot
Alex

The two examples are

a) elements: Carbon and hydrogen  : C(s)   and H2(g)

b) compounds: CO2 and CH4

The reaction is

A + B  ----> C  + D

We know that from law of conservation of mass

Mass of reactants reacted = mass or products formed

Mass of A = 22

Mass of B = 14

Mass of C = 9

Mass of D = (A + B) - (C) = 27 g


8 0
3 years ago
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