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Alla [95]
3 years ago
12

While working in the lab, you observe the following volume.

Chemistry
2 answers:
MakcuM [25]3 years ago
7 0

Answer:

B 18.4L

Explanation:

sp2606 [1]3 years ago
3 0

Answer:

The answer is 18.4 mL

The liquid is between 19 and 17

so the answer will be 18.4 mL

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Option D 2220mmHg

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Is Fluorine more electronegative than<br> Hydrogen?
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8 0
3 years ago
How many grams of liquid CF2Cl2 are needed to cool 156 g of water from 42.9 to 20.5 °C? The specific heat of water is 4.184 J/(g
SashulF [63]

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

CF₂Cl₂ is a refrigerant. When it is evaporated, it absorbs heat from water, which cools.

<h3>What is evaporation?</h3>

Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.

  • Step 1: Calculate the heat released by water.

We will use the following expression.

Qw = c × m × ΔT = (4.184 J/g.°C) × 156 g × (20.5 °C - 42.9 °C)

Qw = -14.6 kJ

where,

  • Qw is the heat released by water.
  • c is the specific heat of water.
  • m is the mass of water.
  • ΔT is the change in the temperature of water.

If water releases 14.6 kJ of heat, CF₂Cl₂ absorbs 14.6 kJ of heat (Qr = 14.6 kJ).

  • Step 2: Calculate the mass of the refrigerant required.

We will use the following expression.

Qr = ΔH°evap × m

m = Qr/ΔH°evap = 14.6 kJ / (0.144 kJ/g) = 101 g

where,

  • Qr is the heat absorbed by the refrigerant.
  • ΔH°evap is the heat of vaporization of the refrigerant.
  • m is the mass of the refrigerant.

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

Learn more about evaporation here: brainly.com/question/25310095

4 0
2 years ago
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