If you look at the model RM is the same length as PM. PM=10 so RM=10.
Answer:
see below
Step-by-step explanation:
The steps are +2 then *4 then -8 then ÷2
Input is 5
5 +2 =7 *4 = 28-8 = 20 ÷2 = 10 Output is 10
Input is 9
9 +2 =11 *4 = 44-8 = 36 ÷2 = 18 Output is 18
Input is 14
14 +2 =16 *4 = 64-8 = 56 ÷2 = 28 Output is 28
Input is 18
18 +2 =20 *4 = 80-8 = 72 ÷2 = 36 Output is 36
Input is 23
23 +2 =25 *4 = 100-8 = 92 ÷2 = 46 Output is 46
Input is 7.5
7.5 +2 =9.5 *4 = 38-8 = 30 ÷2 = 20 Output is 20
Input is 11.54
11.54 +2 =13.54 *4 = 54.16-8 = 46.16 ÷2 = 23.08 Output is 23.08
Hello!
To factor you find the biggest number they can be divided by
The biggest number that all the number can be divided by is 10
You put that outside parenthesis
10()
Divide the expression by 10
3 + x - 4y
Put the two together
10(3 + x + 4y)
Hope this helps!
Answer:
88.88% probability that it endures for less than a year and a half
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

The next career begins on Monday; what is the likelihood that it endures for less than a year and a half?
One year has 52.14 weeks. So a year and a half has 1.5*52.14 = 78.21 weeks.
So this probability is the pvalue of Z when X = 78.21.



has a pvalue of 0.8888
88.88% probability that it endures for less than a year and a half