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3 years ago

4x^2-2x ———— X^2+2x+1

Mathematics

1 answer:

Len [333]3 years ago

4 0

Answer:

x = 0 or x = 1/2 and x = -1 for the second equation

Step-by-step explanation:

Solve for x:

4 x^2 - 2 x = 0

Factor x and constant terms from the left hand side:

2 x (2 x - 1) = 0

Divide both sides by 2:

x (2 x - 1) = 0

Split into two equations:

x = 0 or 2 x - 1 = 0

Add 1 to both sides:

x = 0 or 2 x = 1

Divide both sides by 2:

Answer: x = 0 or x = 1/2

_______________________________

Solve for x:

x^2 + 2 x + 1 = 0

Write the left hand side as a square:

(x + 1)^2 = 0

Take the square root of both sides:

x + 1 = 0

Subtract 1 from both sides:

Answer: x = -1

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2 years ago

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Answer:

$\boxed{a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8+a_9+a_{10}=66}$

Step-by-step explanation:

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We know that:

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We get:

$a_1+a_2=x=\frac{3}{4}\\\\a_3=x=\frac{3}{4}\\\\a_4=2x=\frac{3}{2}\\\\a_5=3x=\frac{9}{4}\\\\a_6=5x=\frac{15}{4}\\\\a_7=8x=6\\\\a_8=13x=\frac{39}{4}\\\\a_9=21x=\frac{63}{4}\\\\a_{10}=34x=\frac{102}{4}\\$

Therefore, we calculate

$\boxed{a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8+a_9+a_{10}=66}$

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434 rounded to the nearest ten is 430.
Hope this helps

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