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mrs_skeptik [129]
3 years ago
15

A car travels at a constant rate for 25 miles, going due east for one hour. Then it travels at a constant rate another 60 miles

east for one hour. What is the instantaneous velocity at any time during the second hour of the trip?
35 mph east
42 mph east
60 mph east
85 mph east
Physics
2 answers:
egoroff_w [7]3 years ago
6 0

60 mph east...........

Ivan3 years ago
4 0

Answer:

The instantaneous velocity at any time during the second hour of the trip is 60 mph east

(C) is correct option

Explanation:

Given that,

Distance in first hour = 25 miles

Distance in second on hour = 60 miles

Instantaneous velocity :

Instantaneous velocity is equal to the distance divided by the time

We need to calculate the instantaneous velocity at any time during the second hour of the trip

Using formula of instantaneous velocity

.v = \dfrac{d}{t}

Where, d = distance

t = time

Put the value into the formula

v = \dfrac{60}{1}

v= 60\ miles/hr

The direction of the instantaneous velocity is in east .

Hence, The instantaneous velocity at any time during the second hour of the trip is 60 mph east

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Explanation:

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6 0
3 years ago
What is latitude 20 degrees north and longitude 65 degrees west?
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3 0
4 years ago
What would be the answer for this and how?
Veronika [31]

Answer:

B. 6 cm

Explanation:

First, we calculate the spring constant of a single spring:

k = \frac{F}{\Delta x}\\

where,

k = spring constant of single spring = ?

F = Force Applied = 10 N

Δx = extension = 4 cm = 0.04 m

Therefore,

k = \frac{10\ N}{0.04\ m}\\k =  250\ N/m\\

Now, the equivalent resistance of two springs connected in parallel, as shown in the diagram, will be:

k_{eq} = k + k\\k_{eq} = 2k = 2(250\ N/m)\\k_{eq} = 500\ N/m\\

For a load of 30 N, applying Hooke's Law:

\Delta x = \frac{F}{k_{eq}}\\\\\Delta x = \frac{30\ N}{500\ N/m}\\\\\Delta x = 0.06\ m = 6\ cm\\

Hence, the correct option is:

<u>B. 6 cm</u>

7 0
3 years ago
an ice skater applies a horizontal force to a 20.-kilogram block on frictionless, level ice, causing the block to accelerate uni
stiv31 [10]
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Apply Newton's 2nd Law in the horizontal direction:
ΣF = ma
F - f = ma
where f = µmg

F - µmg = ma
F = m(a +µg)
F = (20 kg)(1.4 m/s² + 0.28(9.8 m/s²)

F = 83 N
3 0
3 years ago
Newton's first law of motion gives the concept of force moment ​
Furkat [3]

Answer:

Hey there

Where trying to say that:

Newton's first law gives the concept of force and momentum?

That's false if that's is what you said.

Newton's first law tells us that objects in motion will remain in motion and objects at rest will remain at rest.

Newton's second law gives us the concept of force and momentum.

6 0
3 years ago
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