A car travels at a constant rate for 25 miles, going due east for one hour. Then it travels at a constant rate another 60 miles
2 answers:
Answer:
The instantaneous velocity at any time during the second hour of the trip is 60 mph east
(C) is correct option
Explanation:
Given that,
Distance in first hour = 25 miles
Distance in second on hour = 60 miles
Instantaneous velocity :
Instantaneous velocity is equal to the distance divided by the time
We need to calculate the instantaneous velocity at any time during the second hour of the trip
Using formula of instantaneous velocity
.
Where, d = distance
t = time
Put the value into the formula
The direction of the instantaneous velocity is in east .
Hence, The instantaneous velocity at any time during the second hour of the trip is 60 mph east
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Answer:
Xcm = 1.95 cm and Ycm = 1.76 cm
Explanation:
The very useful concept of mass center is
R cm = 1/M ∑
Where ri, mi are the mass positions of the bodies from some reference point by selecting and M is the total mass of the body.
Let's look for the total mass
M = m₁ + m₂ + m₃
M = 140 + 45 + 85
M = 270 g
Let's look for the position of each point
Point 1. top vertex, if the triangle has as side d
R₁ = d / 2 i ^ + d j ^
R₁ = (1.7 cm i ^ + 3.4 j ^) cm
Point 2. left vertex. What is the origin of the system?
R₂ = 0
Point 3. Right vertex
R₃ = d i ^
R₃ = 3.4 i ^ cm
a) The x component of the massage center
Xcm = 1 / M (m₁ x₁ + m₂ x₂ + m₃ x₃)
Xcm = 1 / M (m₁ d / 2 + 0 + m₃ d)
Xcm = d / M (m₁ / 2 + m₃)
b) Let's write the mass center component x
Xcm = 1/270 (1.7 140 + 0 + 3.4 85)
Xcm = 238/270
Xcm = 1.95 cm
c) let's find the component and center of mass
Ycm = 1 / M (m₁ y₁ + m₂ y₂ + m₃ y₃)
Ycm = 1 / M (m₁ d + 0 + 0)
Ycm = m₁ / M d
d) let's calculate
Y cm = 1/270 (140 3.4 + 0 + 0)
Ycm = 1.76 cm