Answer:
The instantaneous velocity at any time during the second hour of the trip is 60 mph east
(C) is correct option
Explanation:
Given that,
Distance in first hour = 25 miles
Distance in second on hour = 60 miles
Instantaneous velocity :
Instantaneous velocity is equal to the distance divided by the time
We need to calculate the instantaneous velocity at any time during the second hour of the trip
Using formula of instantaneous velocity
.
Where, d = distance
t = time
Put the value into the formula
The direction of the instantaneous velocity is in east .
Hence, The instantaneous velocity at any time during the second hour of the trip is 60 mph east
The power is 833.3 W
Explanation:
First of all, we need to calculate the work done in lifting the barbell, which is equal to the change in gravitational potential energy of the barbell:
where
mg = 1250 N is the weight of the barbell
h = 2 m is the change in height
Substituting,
Now we can calculate the power, which is equal to the work done per unit time:
where
W = 2500 J is the work done
t = 3 s is the time taken
Substituting,
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Answer:
sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j
Explanation:
We have given first vector which has length of 7 units and makes an angle of 30° with positive x-axis
So x component of the vector
y component of the vector
So vector will be 6.06i+3.5j
Now other vector of length of 7 units and makes an angle of 120° with positive x-axis
So x component of vector
y component of the vector
Now sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j