Answer:
he gravity of Earth, denoted by g, is the net acceleration that is imparted to objects due to the combined effect of gravitation (from mass distribution within Earth) and the centrifugal force (from the Earth's rotation )
You can solve this by using Newton's First Law or Newton's Second Law.
1) Newton's First Law or Inertia Law states that in the abscense of a net force acting over an object, this will not chage its state of movement, i.e it will remain at rest (if it is no moving) or with uniform movement (if the object is moving).
2) Newton's Second Law: Net force = mass * acceleration => acceleration = net force / mass = 0 / mass = 0.
Zero accelerations means rest or uniform movement.
First Law is implicit in Second Law.
Answer:
(55-0)/10 --> 55 m/s / 10 s --> 5.5 m/s^2
Explanation:
I WANT U TO PARK THAT BIG MACK TRUCK, RIGHT IN THIS LITTLE GRAGE
The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of
<em>F</em> = <em>mg</em> sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N
Then the work done by this force on the crate as it slides down the ramp is
<em>W</em> = <em>F d</em> = (50.3 N) (2.0 m) ≈ 101 J
The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so
<em>W</em> = <em>K</em> = 1/2 <em>mv</em> ^2
Solve for <em>v</em> :
<em>v</em> = √(2<em>W</em>/<em>m</em>) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s
Answer:
see below
Explanation:
let one direction be negative and the other direction be positive
so
right = positive
left = negative
up = positive
down = negative
thus
d) -80 + 100 = 20 N
e) 35 - 55 = -20 N
hope this helps, please mark it brainliest
