The table is:
t(s) vx(m/s)
0 0
10 23
20 46
30 69
a) from the data in the table, we observe that the acceleration is constant (because the rate of change in velocity is the same for each time interval of 10 seconds), so we can choose just one interval and calculate the acceleration as the ratio between the change in velocity and the change in time. Taking the first interval, we find
b) To find the jet's acceleration in g's, we just need to divide the acceleration in m/s^2 by the value of g, the acceleration of gravity (9.81 m/s^2), so we find
c) the wheels leave the ground when the jet reaches its take-off velocity, which is 82 m/s.
At t=0s, the velocity of the jet is 0. We know that the acceleration is constant (a=2.3 m/s^2), so we can find the time t at which the jet reaches a velocity vf=82 m/s by using the equation
Re-arranging and substituting numbers, we find
From the chemical eqn
No of moles of N2O5 = Mass/ molar mass
Molar mass = (14* 2) + (16 *5) = 28 + 90 = 118g.
From the chemical equation 7.9g of NO2 reacts with 7.9 *2 g of N2O5. We have a 1 :2 mole ratio. Hence mass of N2O5 = 14.8g
No of moles = 14.8/ 118 = 0.133 moles.
Answer:
6. Paula is correct. Think about buildings, buildings are constantly pushed by different forces like wind or gravity. The buildings aren’t moving but this doesn’t mean that they aren’t under force
Explanation:
Answer:A) 19.8 seconds
B) 467.5 metres
Explanation: 100km/hr = 27.78m/s
So, it covers 27.78 metres in one second
Take the time it would cover 550m as x
Therefore 27.78m = 1second
550m = x
Cross multiplying
27.78x = 550m
Divide both sides by the coefficient of x
x = 550÷27.78
x = 19.8seconds
B) distance = speed × time
Speed = 85km/hr = 23.61m/s
Time = 19.8seconds
Therefore,
Distance = 23.61 × 19.8
Distance = 467.5m
All Offsprings will be round because it comes out as dominant evrytime and it has 0 ressesives. Hope this helped ;)
