Why does naphthol react with sodium hydroxide? why does ethanol not react to the extent that naphthol does with sodium hydroxide
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1 answer:
Answer:
Conjugate base of naphthol is highly stable but conjugate base of ethanol is unstable.
Explanation:
Naphthol gives acid base reaction with NaOH where naphthol acts as an acid and NaOH as a base.
Reactivity of naphthol towards NaOH is quite high because the conjugate base of naphthol is highly stable. Stability of the conjugate base arises due to delocalization of negative charge on oxygen atom into aromatic naphthalene ring.
Ethanol is not so reactive towards NaOH because the ethoxide ion is highly unstable due to lack of delocalization of negative charge on oxygen atom.
Resonance structures of conjugate base of naphthol has been shown below.
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Hello!
After the addition of a small amount of acid, a reasonable value of buffer pH would be 5,15.
If initially there are equal amounts of a weak acid and its conjugate base, the pH would be equal to the pKa, according to the Henderson-Hasselbach equation:
![pH=pKa+log( \frac{[A^{-}] }{[HA]} ) \\ \\ if [A^{-}]=[HA] \\ \\ pH=pKa + log (1) \\ \\ pH=pKa + 0=5,25](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%20%5Cfrac%7B%5BA%5E%7B-%7D%5D%20%7D%7B%5BHA%5D%7D%20%29%20%5C%5C%20%5C%5C%20if%20%5BA%5E%7B-%7D%5D%3D%5BHA%5D%20%5C%5C%20%5C%5C%20pH%3DpKa%20%2B%20log%20%281%29%20%5C%5C%20%5C%5C%20pH%3DpKa%20%2B%200%3D5%2C25)
So, when adding a little amount of acid the pH should be only a little lower than the pKa. The value from the list that is a little lower than the pKa is 5.15
Have a nice day!
After the addition of a small amount of acid, a reasonable value of buffer pH would be 5,15.
If initially there are equal amounts of a weak acid and its conjugate base, the pH would be equal to the pKa, according to the Henderson-Hasselbach equation:
So, when adding a little amount of acid the pH should be only a little lower than the pKa. The value from the list that is a little lower than the pKa is 5.15
Have a nice day!