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anyanavicka [17]
3 years ago
11

How can i solve this​

Physics
1 answer:
ozzi3 years ago
8 0

Answer:

Que?     ME NO UnderStand DJn

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Observe and compare the forces acting on the turtle and the cat.
Pepsi [2]

Answer:

The forces are balanced on both animals because they are not moving

More importantly than not moving is not <u>accelerating.</u>

Explanation:

5 0
3 years ago
Since you've determined that the power supply is a 700W dual rail, what does that make the maximum output power?
inysia [295]

700 makes the maximum output power.

<u>Explanation:</u>

In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft.

A joule is equal to one Newton-meter, which is the amount of work needed to move a 1 Newton force a distance of 1 meter. When you divide work by time, you get power, measured in units of joules per second. This is also called a Watt. 1 Watt = 1 Joule Sec. This is the formula to calculate output power.

6 0
3 years ago
WHO LIKES ROGUE ONE AND CLONE WARS AND IS ADDICTED TO STAR WARS AND WOULD WISH THAT YOU COULD WORK WITH DAVE FILONI. Same bro Sa
scoray [572]

Answer:

heck ya its so fire

Explanation:

3 0
3 years ago
Please help me thank you !!!!
Fantom [35]

Answer:

<em>UP</em>

Explanation:

heat flows from higher level to lower level

( higher concentration to lower concentration )

and since temperature in above block is less than the lower block, the heat will flow from lower block to higher block .

( Up )

5 0
3 years ago
If you put 120 volts of electricity through a pickle, the pickle will smoke and start glowing orange-yellow. The light is emitte
Alona [7]

Answer:

2.11eV

Explanation:

We know that speed of light is it's wavelength times frequency.

\therefore f=v/\lambda\\=(3\times10^8m/s)/(589mm\times1m/1\times 10^9nm)\\=5.09\times10^1^4s^-1 \ or \ 5.09\times10^1^4Hz

Planck's constant is 6.626\times 10^3^4Js

The energy gap is calculated by multyplying the light's frequency by planck's constant:

E_c=5.09\times10^1^4s^-^1\times 6.626\times10^-^3^4Js\\\\=3.37\times 10^-^1^9J  \ \ \ \ \ \ #1eV=1.06\times 10^-^1^9J\\\\=2.11eV

Hence, the energy gap is 2.11eV

4 0
3 years ago
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