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AURORKA [14]
3 years ago
15

Given a block of glass that is semi-circular, a laser pointer, protractor/ruler, and index card, design your own experiment to o

bserve and measure total internal reflection. Describe how you would shine the laser onto the glass block, what angles you would measure and how you would determine the critical angle from your measurements.
Physics
2 answers:
leonid [27]3 years ago
7 0

Answer:

Explanation:

Critical angle is angle of incidence at which the reflected ray is perpendicular to the normal of the plane.

Apply snell's law,

    ni sin∅i = nr sin ∅r

Here,ni & nr are reflective indices of incident and refracted media ,∅i is angle of incidence and ∅r is angle of refraction

In this case,the light refracted at interface of glass -air medium

ni=(1.52), nr =1.00(for air),∅r=90° and ∅i =∅c(from the definition of critical angle),

(1.52)sin∅c = (1.00)sin 90°

solve the equation for ∅c

∅c=sin⁻¹{(1.00)sin 90° /1.52}

=41.1°

thus,the critical angle is 41.1° .The rays which are incident greater than this angle,would reflect back into the same glass medium(total internal reelection)

Charra [1.4K]3 years ago
5 0

Answer:

we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

Explanation:

To design the experiment of measuring the critical angle, we describe the phenomenon, when the light passes from a medium with a higher refractive index to one with a lower index, it separates from the normal one and the Critical Angle is defined as the Angle for which the refraction occurs at 90º

            n₂ sin θ₂ = n₁ sin 90

           n₁ / n₂ = sin θ₂

As we can see, we have to measure the angle with which the laser touches the exit surface of the glass block.

Design of the experiment:

    We place the glass block on the ramp and at the top we hit the conveyor for half the angle, we climb the block on the ramp and see that the angle of incidence of lightning on the exit face changes, part of the beam comes out of the glass , we see it by dispersion in the particles of dirty in the air; Maybe the conveyor or the laser should be moved slightly so that the beam touches the point of origin on the conveyor.

   

   When we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

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NISA [10]

This looks complicated, but it's actually not too tough.

The formula for the gravitational force between two objects is

              Force = G  (one mass) (other mass) / (distance²) .

The question GAVE us all of those numbers except the distance.
All we have to do is pluggum in, massage it around, and find
the distance. 

Force  =         4.18 x 10¹⁵     N
  G  =             6.673 x 10⁻¹¹  N·m²/kg²
One mass =   6.58 x 10²³     kg
Other mass = 9.3 x 10¹⁵       kg   .

The only tricky thing about this is gonna be the arithmetic ...
keeping all the exponents straight.

Take the formula for the gravitational force and plug in
everything we know:

Force = (G) · (one mass) · (other mass) / (distance²) 

4.18x10¹⁵N = (6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) / (distance²).

Multiply each side by  (distance²):

(distance²)·(4.18x10¹⁵N) = (6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) 

Divide each side by  (4.18 x 10¹⁵ N) :

(distance²)=(6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) / (4.18x10¹⁵N)

That's the end of the Physics and Algebra.  The only thing left is Arithmetic.
We have to simplify that whole ugly thing on the right side of the equation,
and then take the square root of each side.

When I crunch down the right side of that equation, I get

           (distance²)  =  9.769 x 10¹³  m²

and when I take the square root of each side, I get

             distance  =  9.884 x 10⁶ meters .   **

You should check my Arithmetic.   **
(Pause occasionally to let your calculator cool off.)


BY THE WAY ... 
That "distance" in the equation for gravitational force is the distance
between the CENTERS of the two objects. 
This doesn't make much difference for Phobos, because Phobos isn't
much bigger than a big sweet potato.  But it does make a difference for
Mars. 
The 'distance' we find with all of this nonsense is NOT the distance
between Phobos and the surface of Mars.  It's the distance between 
Phobos and the CENTER of Mars, so it includes the planet's radius.   


** Consulting online resources between Floogle and Flickerpedia,
I found that the orbital distance of Phobos from Mars varies between
9,234 km and 9,517 km.  Add the planet's radius to these, and I'm
beginning to feel confidence in the results of my back-of-the-napkin
calculation.  But you should still check my Arithmetic.

5 0
3 years ago
A web page designer creates an animation in which a dot on a computer screen has a position of r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i
VMariaS [17]

Answer:

V = (5.8cm/s)i, (4.7cm/s)j

Explanation:

Given :

r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i^+( 4.70 cm/s )tj^

To obtain the average velocity (V)

V = (r2 - r1) / (t2 - t1)

To obtain r1 and r2, substitute t1 = 0 and t2 = 2 respectively in the equation above

r1 = [ 4.50 cm +( 2.90 cm/s2 ) 0]i^+( 4.70 cm/s )0 j

r1 = 4.50 cm + 0 + 0 = (4.50cm)i + 0j

r2 = [ 4.50 cm +( 2.90 cm/s2 )2²]i^+( 4.70 cm/s )2 j

r2 = 4.50cm + (2.90 × 4)i + (4.70 × 2)j

r2 = (16.1cm)i + (9.4cm)j

V = [(16.1 - 4.50)i - (9.4 - 0)j] / 2 - 0

V = 11.6i / 2 ; 9.4j / 2

V = (5.8cm/s)i, (4.7cm/s)j

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3 years ago
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Two long, straight wires are separated by 0.120 m. The wires carry currents of 11 A in opposite directions, as the drawing indic
rewona [7]

Answer:

The magnitude of the magnetic field is 1.83 x 10^{-5} T.

Explanation:

The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.

In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.

The magnetic field (B) between the given wires can be determined by:

B = \frac{U_{o}I }{2\pi r}

where: I is the current, r is the distance between the wires and U_{0} is the magnetic field constant.

But, I = 11 A, r = 0.12 m and U_{0} = 4\pi x 10^{-7} Tm/A

So that;

B = \frac{4\pi *10^{-7}*11 }{2\pi *0.12}

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6 0
2 years ago
To move a refrigerator of mass 170 kg into a house, a mover puts it on a dolly and covers the steps leading into the house with
Arte-miy333 [17]

Explanation:

The given data is as follows.

         mass (m) = 170 kg,        Distance (s) = 9.6 m

        Height (h) = 3.3 m,         Force (F) = 1400 N

First, we will calculate the work performed by her as follows.

                W = Fs

                    = 1400 N \times 9.6 m

                    = 13440 J

Hence, minimal work necessary to lift the refrigerator is as follows.

               U = mgh

                   = 170 kg \times 9.8 \times 3.3 m

                   = 5497.8 J

Therefore, we can conclude that he performed 5497.8 J of work.

7 0
3 years ago
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