This looks complicated, but it's actually not too tough.
The formula for the gravitational force between two objects is
Force = G (one mass) (other mass) / (distance²) .
The question GAVE us all of those numbers except the distance.
All we have to do is pluggum in, massage it around, and find
the distance.
Force = 4.18 x 10¹⁵ N
G = 6.673 x 10⁻¹¹ N·m²/kg²
One mass = 6.58 x 10²³ kg
Other mass = 9.3 x 10¹⁵ kg .
The only tricky thing about this is gonna be the arithmetic ...
keeping all the exponents straight.
Take the formula for the gravitational force and plug in
everything we know:
Force = (G) · (one mass) · (other mass) / (distance²)
4.18x10¹⁵N = (6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) / (distance²).
Multiply each side by (distance²):
(distance²)·(4.18x10¹⁵N) = (6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg)
Divide each side by (4.18 x 10¹⁵ N) :
(distance²)=(6.673x10⁻¹¹N-m²/kg²)·(6.58x10²³kg)·(9.3x10¹⁵kg) / (4.18x10¹⁵N)
That's the end of the Physics and Algebra. The only thing left is Arithmetic.
We have to simplify that whole ugly thing on the right side of the equation,
and then take the square root of each side.
When I crunch down the right side of that equation, I get
(distance²) = 9.769 x 10¹³ m²
and when I take the square root of each side, I get
distance = 9.884 x 10⁶ meters . **
You should check my Arithmetic. **
(Pause occasionally to let your calculator cool off.)
BY THE WAY ...
That "distance" in the equation for gravitational force is the distance
between the CENTERS of the two objects.
This doesn't make much difference for Phobos, because Phobos isn't
much bigger than a big sweet potato. But it does make a difference for
Mars.
The 'distance' we find with all of this nonsense is NOT the distance
between Phobos and the surface of Mars. It's the distance between
Phobos and the CENTER of Mars, so it includes the planet's radius.
** Consulting online resources between Floogle and Flickerpedia,
I found that the orbital distance of Phobos from Mars varies between
9,234 km and 9,517 km. Add the planet's radius to these, and I'm
beginning to feel confidence in the results of my back-of-the-napkin
calculation. But you should still check my Arithmetic.
Answer:
V = (5.8cm/s)i, (4.7cm/s)j
Explanation:
Given :
r⃗ =[ 4.50 cm +( 2.90 cm/s2 )t2]i^+( 4.70 cm/s )tj^
To obtain the average velocity (V)
V = (r2 - r1) / (t2 - t1)
To obtain r1 and r2, substitute t1 = 0 and t2 = 2 respectively in the equation above
r1 = [ 4.50 cm +( 2.90 cm/s2 ) 0]i^+( 4.70 cm/s )0 j
r1 = 4.50 cm + 0 + 0 = (4.50cm)i + 0j
r2 = [ 4.50 cm +( 2.90 cm/s2 )2²]i^+( 4.70 cm/s )2 j
r2 = 4.50cm + (2.90 × 4)i + (4.70 × 2)j
r2 = (16.1cm)i + (9.4cm)j
V = [(16.1 - 4.50)i - (9.4 - 0)j] / 2 - 0
V = 11.6i / 2 ; 9.4j / 2
V = (5.8cm/s)i, (4.7cm/s)j
A poll watcher
<span>a person who is paid by the parties to watch the voters and officials to make sure everything is fair</span>
Answer:
The magnitude of the magnetic field is 1.83 x
T.
Explanation:
The flow of an electric current in a straight wire induces magnetic field around the wire. When current is flowing through two wires in the same direction, a force of attraction exists between the wires. But if the current flows in opposite directions, the force of repulsion is felt by the wires.
In the given question, the direction of flow of current through the wires is opposite, thus both wires applies the same field on each other. The result to repulsion between them.
The magnetic field (B) between the given wires can be determined by:
B = 
where: I is the current, r is the distance between the wires and
is the magnetic field constant.
But, I = 11 A, r = 0.12 m and
= 4
x
Tm/A
So that;
B = 
= 1.8333 x 
B = 1.83 x
T
Explanation:
The given data is as follows.
mass (m) = 170 kg, Distance (s) = 9.6 m
Height (h) = 3.3 m, Force (F) = 1400 N
First, we will calculate the work performed by her as follows.
W = Fs
= 
= 13440 J
Hence, minimal work necessary to lift the refrigerator is as follows.
U = mgh
= 
= 5497.8 J
Therefore, we can conclude that he performed 5497.8 J of work.