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AURORKA [14]
3 years ago
15

Given a block of glass that is semi-circular, a laser pointer, protractor/ruler, and index card, design your own experiment to o

bserve and measure total internal reflection. Describe how you would shine the laser onto the glass block, what angles you would measure and how you would determine the critical angle from your measurements.
Physics
2 answers:
leonid [27]3 years ago
7 0

Answer:

Explanation:

Critical angle is angle of incidence at which the reflected ray is perpendicular to the normal of the plane.

Apply snell's law,

    ni sin∅i = nr sin ∅r

Here,ni & nr are reflective indices of incident and refracted media ,∅i is angle of incidence and ∅r is angle of refraction

In this case,the light refracted at interface of glass -air medium

ni=(1.52), nr =1.00(for air),∅r=90° and ∅i =∅c(from the definition of critical angle),

(1.52)sin∅c = (1.00)sin 90°

solve the equation for ∅c

∅c=sin⁻¹{(1.00)sin 90° /1.52}

=41.1°

thus,the critical angle is 41.1° .The rays which are incident greater than this angle,would reflect back into the same glass medium(total internal reelection)

Charra [1.4K]3 years ago
5 0

Answer:

we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

Explanation:

To design the experiment of measuring the critical angle, we describe the phenomenon, when the light passes from a medium with a higher refractive index to one with a lower index, it separates from the normal one and the Critical Angle is defined as the Angle for which the refraction occurs at 90º

            n₂ sin θ₂ = n₁ sin 90

           n₁ / n₂ = sin θ₂

As we can see, we have to measure the angle with which the laser touches the exit surface of the glass block.

Design of the experiment:

    We place the glass block on the ramp and at the top we hit the conveyor for half the angle, we climb the block on the ramp and see that the angle of incidence of lightning on the exit face changes, part of the beam comes out of the glass , we see it by dispersion in the particles of dirty in the air; Maybe the conveyor or the laser should be moved slightly so that the beam touches the point of origin on the conveyor.

   

   When we go up the ramp there is a point where the beam is reflected inside the block, we carefully step back to the point where the beam is horizontal, we measure this angle which is our critical angle.

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irina1246 [14]

Answer:

A.Gravity acts to pull the object down

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E.The path of the object is curved.

Explanation:

The motion of a projectile consists of two independent motions:

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- A vertical motion with constant acceleration of g = 9.8 m/s^2 downward (acceleration due to gravity), due to the presence of the force of gravity, so the vertical velocity changes (increases in the downward direction)

As a result, the combined motion of the projectile has a curved trajectory (parabolic, more specifically). So the following options are correct:

A.Gravity acts to pull the object down --> gravity acts along the vertical direction

D.The object’s inertia carries it forward. --> there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal motion continues with constant speed

E.The path of the object is curved

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Two protons in an atomic nucleus are typically separated by a distance of 2 ✕ 10-15 m. The electric repulsion force between the
castortr0y [4]

Answer:

The magnitude of the electric force between the to protons will be 57.536 N.

Explanation:

We can use Coulomb's law to find out the force, in scalar form, will be:

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Now, making the substitutions

d \ = \ 2.00 * 10 ^{-15} \ m,

q_1 = q_2 = 1.60 * 10 ^ {-19} \ C,

\frac{1}{4\pi\epsilon_0}=8.99 * 10^9 \frac{Nm^2}{C^2},

we can find:

F \ = \ 8.99 * 10^9 \frac{Nm^2}{C^2} \frac{(1.60 * 10 ^ {-19} \ C)^2}{(2.00 * 10 ^{-15} \ m)^2}.

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4 0
3 years ago
Read 2 more answers
A steel beam that is 5.50 m long weighs 332 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending
ElenaW [278]

Explanation:

The given data is as follows.

    Length of beam, (L) = 5.50 m

    Weight of the beam, (W_{b}) = 332 N

     Weight of the Suki, (W_{s}) = 505 N

After crossing the left support of the beam by the suki then at some overhang distance the beam starts o tip. And, this is the maximum distance we need to calculate. Therefore, at the left support we will set up the moment and equate it to zero.

                 \sum M_{o} = 0

     -W_{s} \times x + W_{b} \times 1.5 = 0

                x = \frac{W_{b} \times 1.5}{W_{s}}

                   = \frac{332 N \times 1.5}{505 N}

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Hence, the suki can come (2 - 0.986) m = 1.014 from the end before the beam begins to tip.

Thus, we can conclude that suki can come 1.014 m close to the end before the beam begins to tip.

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