1. The area of one face of the bar is
.. face area = (50 mm)*(90 mm) = 4500 mm^2
The area of two sides of the bar is
.. side area = (50 mm +90 mm)*(3.5 mm) = 490 mm^2
Together, those areas cover half the bar, so the total paper required is
.. 2*(4500 mm^2 +490 mm^2) = 9980 mm^2 . . . . . . 3rd selection
2. The length of the central rectangle is
.. 8 ft + 6 ft + 10 ft = 24 ft
Its width is 7 ft, so its area is
.. Arect = (7 ft)*(24 ft) = 168 ft^2
Each of the two triangles has a base of 8 ft and a height of 6 ft, so together, they have an area of
.. Atriangles = (8 ft)*(6 ft) = 48 ft^2
Then the total area of the prism is
.. Atotal = Arect +Atriangles
.. = (168 ft^2) +(48 ft^2)
.. = 216 ft^2
So slope intercept form y=mx+b slope is m
m=6 so
y=6x+b
this is not the legit way but it works so
put in 3 for x and 4 for y and solve for b
4=6(3)+b
4=18+b
-14=b
b=-14
the slope intercep form is y=6x-14
The answer would be 1/p^5q^0 so Brianna is correct. If you took it a step further, the answer would be 1/p^5 because any number (except 0) or variable raised to the zero power is 1.
im assuming i just pick two angles cause i cant see the options? two 90 degree angles.
and my name is teagan too :D
