Answer:
0.135E-19kgm/s
Explanation:
Using the uncertainty principle, we find
Dp = h / (4π Dx)
 = (6.63×10-34Js)/4π(3.90×10-15m) = 0.135×10-19kg m/s
 
        
             
        
        
        
I believe that the answer to the question provided above is that with increase in resistance provided with constant current, Power dissipated will be lessen since power loss is high. Low power dissipation has low heat production.
Hope my answer would be a great help for you.  
        
             
        
        
        
The answer is c nitrogen thx me later
        
             
        
        
        
Answer:
 p = 6.64 cm
Explanation:
For this exercise we use the equation of the constructor
           
where f is the focal length, p and q are the distance to the object and the image, respectively
They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image
            
           1 / p = 1 / 2.2 - 1/3.29
            1 / p = 0.15059
            p = 6.64 cm
therefore the farthest distance from the object is 6.64 c
 
        
             
        
        
        
Answer:
There is a loss of fluid in the  container of 0.475L
Explanation:
To solve the problem it is necessary to take into account the concepts related to the change of voumen in a substance depending on the temperature.
The formula that describes this thermal expansion process is given by:

Where,
 Change in volume
Change in volume
 Initial Volume
Initial Volume
 Change in temperature
 Change in temperature
 coefficient of volume expansion (Coefficient of copper and of the liquid for this case)
 coefficient of volume expansion (Coefficient of copper and of the liquid for this case) 
There are two types of materials in the container, liquid and copper, so we have to change the amount of Total Volume that would be subject to,

Where,
 = Change in the volume of liquid
= Change in the volume of liquid
 = Change in the volume of copper
= Change in the volume of copper
Then replacing with the previous equation we have:


Our values are given as,
Thermal expansion coefficient for copper and the liquid to 20°C is




Replacing we have that,



Therefore there is a loss of fluid in the container of 0.475L