How far does the bullet penetrate and how do I figure this out?

A train has a constant velocity of 2 m/s. east what is the magnitude of the horizontal acceleration of the trian?

kupik [55]

Answer:

0 m/s²

Explanation:

The velocity is constant, so there is no acceleration.

4 0

3 years ago

1. A man is running on the straight road with the uniform velocity

Rufina [12.5K]

None he is undergoing constant uniform velocity. Acceleration is the rate of change of velocity

8 0

3 years ago

Read 2 more answers

A couple of astronauts agree to rendezvous in space after hours. Their plan is to let gravity bring them together. She has a mas

Oduvanchick [21]

Answer:

(a) Acceleration of female astronaut = 9.33*10^-12 m/s^2; Acceleration of male astronaut = 7.56*10^-12 m/s^2

(b) 27.013 days

(c) No, their accelerations would not be constant.

Explanation:

In the given question, we have:

Mass of female astronaut $M_{1}$ = 60.0 kg

Mass of male astronaut $M_{2}$ = 74.0 kg

Distance between them (S) = 23.0 m

(a) The free-body diagram is shown in the attached figure.

Using the equations below, the initial accelerations of the two astronauts can be calculated:

Force of gravity (F) = $\frac{G*M_{1}*M_{2}}{S^{2} }$

G = 6.67*10^-11 $\frac{m^{3} }{kg*s^{2} }$

F = (6.67*10^-11 *60*74)/23^2 = 5.598*10^-10 N

For the female astronaut, her initial acceleration = F/ $M_{1}$ = 5.598*10^-10/60 = 9.33*10^-12 m/s^2

For the male astronaut, his acceleration = F/ $M_{2}$ = 5.598*10^-10/74 = 7.56*10^-12 m/s^2

(b) Since the different between their mass is not much, we can deduce that:

$a_{average} = \frac{a_{1}+a_{2}}{2}$ = (9.33*10^-12 + 7.56*10^-12)/2 = 8.445*10^-12 m/s^2

Using the equation below, we can calculate the the time:

S = ut + 1/2 (at^2) where u = 0

23 = 1/2 (8.445*10^-12)*t^2

t^2 = 5.447*10^12

t = 2333883.044 s = 27.013 days

(c) No, their accelerations will not be constant. It will increase because their radii would be decreasing.

8 0

3 years ago

4. In the Exploration, the sled does not move at all when two equal forces are applied

Assoli18 [71]

Answer:

The net force is zero, so the acceleration is zero

Explanation:

Newton's second law states that the acceleration of an object is proportional to the net force applied to it, according to the equation:

$\sum F = ma$ (1)

where

$\sum F$ is the net force on the object

m is the mass of the object

a is its acceleration

In this problem, we have a sled acted upon two forces, $F_1, F_2$ . So the net force on the sled is

$\sum F = F_1 + F_2$ (2)

however, we are told that the two forces are equal in magnitude but in opposite directions, so

$F_1 = F\\F_2 = -F$

So, eq.(2) becomes

$\sum F = F+(-F) = 0$

and so eq.(1) becomes

$\sum F = ma = 0$

which means

$a=0$

so the acceleration of the sled is zero, and if the sled was at rest, it will not move.

7 0

3 years ago

A 30 kg buzzard is sitting on a cable. The cable is attached to two poles 25

sertanlavr [38]

Answer:

T1 = 675 [N] ; T2 = 707.5 [N]

Explanation:

To solve this problem we must draw a free body diagram, where the bird is located, the posts and distances mentioned.

In the attached image we can see the free body diagram with different forces, angles and distances.

By conducting a distance analysis we can find the angles on both sides of the rope relative to the horizontal.

Then we perform a force analysis on the X-axis and the y-axis in order to find the two equations we need to find the stresses in the cables (T1 & T2)

6 0

3 years ago